mysql如果然後選擇語句

我有一個fullcalendar保留。我想在10個預訂日期顯示全部。而且我還希望在相應的日期顯示用戶預訂，以便他知道他是否已在該日期預訂。 event.title可能是全部或我的預訂。如果它有10個預訂，則event.title是全部。如果用戶對該日期有保留，event.title是我的保留,eventSource是來自數據庫的JSON編碼數據。下面的代碼實際上是在展示全部，但它不包括我的預訂呢。mysql如果然後選擇語句

SELECT CONCAT('FULL') as title, counter, datee as start 
    FROM (
     SELECT DATE_FORMAT(dateR, '%Y-%m-%d') AS datee, 
      COUNT(ID) AS counter 
      FROM reservations 
     GROUP BY datee 
     )q 
WHERE counter=10

我嘗試使用case但它似乎#1242 - Subquery returns more than 1 row。

SELECT 
    (case 
    when (select counter 
      FROM (
       SELECT DATE_FORMAT(dateR, '%Y-%m-%d') AS datee, 
       COUNT(ID) AS counter 
       FROM reservations 
       GROUP BY datee 
       ) q) = 10 
      then "full" 
    end) 
    as title;

Zoomin：

(
    SELECT DATE_FORMAT(dateR, '%Y-%m-%d') AS datee, 
    COUNT(ID) AS counter 
    FROM reservations 
    GROUP BY datee 
) q

來源

2016-07-28 d_unknown

顯示我們從'reservations'表中的一些樣本數據將在這裏很長的路要走。 –

Tim它派生表q – Drew

派生表'q'返回多於一行。它變成了外包裝上的計數器。您正在比較多行以便像3 – Drew

爲了模擬if語句，你可以使用case。也許這是你在找什麼：

SELECT CASE WHEN counter = 10 THEN 'FULL' ELSE 'MY RESERVATION' END as title, 
    counter, datee as start 
FROM (
    SELECT DATE_FORMAT(dateR, '%Y-%m-%d') AS datee, COUNT(ID) AS counter 
    FROM reservations 
    GROUP BY datee 
    ) q

來源

2016-07-28 03:53:06 sgeddes

SELECT ymd, if (counter > 9, 'FULL', 'MY RESERVATION') AS Title 
FROM (
    SELECT date(dateR) AS ymd, count(*) AS counter 
    FROM reservations 
    GROUP BY 1 
) AS t

甚至更好：

SELECT date(dateR) AS ymd, if (count(*) > 9, 'FULL', 'MY RESERVATION') AS Title 
FROM reservations 
GROUP BY 1

來源

2016-07-28 03:58:08 SIDU

mysql如果然後選擇語句

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