javax.xml.transform.Transformer忽略前綴？

Question

我試圖解析一個很簡單的例子：

<?xml version="1.0" encoding="UTF-8"?> 
<root xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'> 
    <openSearch:totalResults>100</openSearch:totalResults> 
</root> 

我使用的樣式表如下：

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
       version="1.0" 
       xmlns:app='http://www.w3.org/2007/app' > 
<xsl:output method="xml" indent="yes"/> 
<xsl:preserve-space elements="*"/> 
<xsl:template match="/"> 
    <results> 
     <xsl:attribute name="total-results"> 
       <xsl:value-of 
       select="atom:root/openSearch:totalResults"/> 
     </xsl:attribute> 
    </results> 
</xsl:template> 
</xsl:stylesheet> 

這工作在的libxslt，沒有問題。我正試圖在java中執行相同的任務，並且正在嘗試使用javax.xml.transform包來執行此操作。它不是預期的結果，它爲總結果屬性提供了一個空值。但是，當我改變這個值：

   <xsl:value-of select="root/totalResults"/> 

它的工作原理。更改xml和xslt不是一個選項。有一個參數我應該設置在某個地方？代碼非常簡單：

InputSource xmlSource = new InputSource(new StringReader(xml)); 

DocumentBuilder builder = factory.newDocumentBuilder(); 
document = builder.parse(xmlSource); 

// Use a Transformer for output 
TransformerFactory tFactory = TransformerFactory.newInstance(); 


StreamSource stylesource = new StreamSource(new StringReader(styleSheet)); 
Transformer transformer = tFactory.newTransformer(stylesource); 

StringWriter writer = new StringWriter(); 

DOMSource source = new DOMSource(document); 
StreamResult result = new StreamResult(writer); 
transformer.transform(source, result); 

stringResult = writer.toString(); 

Answer 1

在樣式表中，您缺少「atom」和「openSearch」的名稱空間聲明。 以下工作：

1. 添加了「OpenSearch的」命名空間（從XML複製）在樣式表
2. 刪除了「原子」命名空間，因爲有
3. 將工廠作爲本 名字空間中沒有信息命名空間意識到：factory.setNamespaceAware(true);

這裏是Scala的完整代碼（對不起，我是懶得解析該文件中的XML和樣式表或在Java中做字符串連接）：

def testxsl = { 
     val xml = """<?xml version="1.0" encoding="UTF-8"?> 
<root xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'> 
    <openSearch:totalResults>100</openSearch:totalResults> 
</root> 
     """ 
     val styleSheet = """<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" 
     xmlns:app='http://www.w3.org/2007/app' 
     xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'> 
<xsl:output method="xml" indent="yes"/> 
<xsl:preserve-space elements="*"/> 
<xsl:template match="/"> 
    <results> 
     <xsl:attribute name="total-results"> 
       <xsl:value-of select="root/openSearch:totalResults"/> 
     </xsl:attribute> 
    </results> 
</xsl:template> 
</xsl:stylesheet> 
     """ 
    val xmlSource = new InputSource(new StringReader(xml)); 
    val factory = DocumentBuilderFactory.newInstance(); 
    factory.setNamespaceAware(true); 
    val builder = factory.newDocumentBuilder(); 
    val document = builder.parse(xmlSource); 

    // Use a Transformer for output 
    val tFactory = TransformerFactory.newInstance(); 


    val stylesource = new StreamSource(new StringReader(styleSheet)); 
    val transformer = tFactory.newTransformer(stylesource); 

    val writer = new StringWriter(); 

    val source = new DOMSource(document); 
    val result = new StreamResult(writer); 
    transformer.transform(source, result); 
    writer.toString(); 
    }