我最近在Java中使用了AES CBC 128算法來加密數據。現在我需要在PHP中重建該算法,但我不知道如何,因爲互聯網上的PHP算法返回不同的結果。也許你可以幫助我。使用Java和PHP的AES CBC 128位加密
這是Java代碼進行加密:
private SecretKeySpec secretKey;
private IvParameterSpec ivSpec;
public void setKey(String myKey) {
MessageDigest sha = null;
try {
byte[] key = myKey.getBytes("UTF-8");
sha = MessageDigest.getInstance("SHA-1");
key = sha.digest(key);
key = Arrays.copyOf(key, 16);
secretKey = new SecretKeySpec(key, "AES");
byte[] iv = new String("1010101010101010").getBytes("UTF-8");
ivSpec = new IvParameterSpec(iv);
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
}
public String encrypt(String strToEncrypt) {
try {
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.ENCRYPT_MODE, secretKey, ivSpec);
return Base64.encode(cipher.doFinal(strToEncrypt.getBytes("UTF-8")));
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
public String decrypt(String strToDecrypt) {
try {
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, secretKey, ivSpec);
return new String(cipher.doFinal(Base64.decode(strToDecrypt)));
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
public static void main(String[] args) {
AESText aes = new AESText();
final String secretKey = "com.secure.test.projectjasdS/FjkGkGhkGjhG786Vjfg=tjGFGH";
aes.setKey(secretKey);
String originalString = "test set se ts et set s et se";
String encryptedString = aes.encrypt(originalString);
String decryptedString = aes.decrypt(encryptedString);
System.out.println("origin: " + originalString);
System.out.println("encrypted: " + encryptedString);
System.out.println("decrypted: " + decryptedString);
}
這是我的PHP代碼:
protected $key;
protected $method = 'AES-128-CBC';
protected $iv = '1010101010101010';
protected $option = OPENSSL_CIPHER_AES_128_CBC;
function __construct($key)
{
$this->key = $key;
}
public function encrypt($data) {
if (is_null($data)) {
return "Error " . INVALID_PARAMS_ENCRYPTIONS . ": Data is null ";
}
$enc = openssl_encrypt($data, $this->method, $this->key, $this->option, $this->iv);
return base64_encode($enc);
}
public function decrypt($data) {
if (is_null($data)) {
return "Error " . INVALID_PARAMS_ENCRYPTIONS . ": Data is null ";
}
$data = base64_decode($data);
$dec = openssl_decrypt($data, $this->method, $this->key, $this->option, $this->iv);
return $dec;
}
當我從Java加密方法加密的數據,這個結果不能在PHP解密解密。
你們可能可以幫我建立一個PHP腳本,它返回與java加密相同的結果嗎?
謝謝@Shastick。我是加密的初學者。我編輯了我的java代碼。當我在java中使用'PKCS5Padding'時,這是工作,但是當我使用'NoPadding'時,出現錯誤'javax.crypto.IllegalBlockSizeException:輸入長度不是16字節的倍數'。但是,當我用'PKCS5Padding'添加'IV'並將'ECB'更改爲'CBC'時,java和php之間的加密不匹配。你能幫我編輯我的代碼嗎? –
那麼,當輸入長度不是16的倍數時,填充是填充整體的,正如在異常中提到的那樣:)您可能需要多玩一點,然後查找一些教程以使其正確。 – Shastick