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如何我有一個個人頁面,管理員可以修改配置文件的用戶, 一個頁面上的所有過程中完成的,我怎麼能更新值形式的數據查詢成功更新後刷新? User.class文件:更新值輸入表單類結果
class User {
...
public function updateUser($id, $firstname, $lastname, $phone, $birthday, $managerid)
{
$con = $this->DBconnect();
$id = (int)$id;
$managerid = $this->checkParam($managerid);
$firstname = $firstname;
$lastname = $lastname;;
$mobile = $phone;
$birthday = $this->checkParam($birthday);
$query = "UPDATE `users` SET `manager_id` = :manager_id,`firstname` = :firstname,`lastname` = :lastname,`birthday` = :birthday,`mobile` = :mobile WHERE `id` = :id";
$result = $con->prepare($query);
$result->BindParam(':id', $id, PDO::PARAM_INT);
$result->BindParam(':manager_id', $managerid, PDO::PARAM_INT);
$result->BindParam(':firstname', $firstname);
$result->BindParam(':lastname', $lastname);
$result->BindParam(':birthday', $birthday);
$result->BindParam(':mobile', $mobile);
$check = $result->execute();
return true;
}}
profile.php文件:
<?php
if (isset($_GET['id'])) {
$id = (int)$_GET['id'];
}
$user = new User();
$user_info = $user->getuser($id);
while ($info = $user_info->fetch(PDO::FETCH_ASSOC)) {
$firstname = $info['firstname'];
$lastname = $info['lastname'];
$mobile = $info['mobile'];
$birthday = $info['birthday'];
$managerid = $info['manager_id'];
}
$manager_ob = new Manager();
$managers = $manager_ob->getAllManager();
$managers_name = array();
while ($manager = $managers->fetch(PDO::FETCH_ASSOC)) {
$managers_list[] = $manager;
}
if (isset($_POST['edit-profile'])) {
$update_result = $user->updateUser($_POST['user_id'],$_POST['user_firstname'],$_POST['user_lastname'],$_POST['user_mobile'],$_POST['user_birthday'],$_POST['manager_id']);
if($update_result){
echo 'Profile Edited';
}
}
?>
<form method="post" action="#" class="form-horizontal">
<div class="form-group"><label class="col-sm-2 control-label">ID</label>
<div class="col-sm-10"><input type="text" readonly class="form-control" name="user_id" id="user_id" value="<?php echo check_param($id); ?>"/></div>
</div>
<div class="form-group"><label class="col-sm-2 control-label">Firstname</label>
<div class="col-sm-10"><input type="text" class="form-control" name="user_firstname" value="<?php echo check_param($firstname); ?>" /></div>
</div>
<div class="form-group"><label class="col-sm-2 control-label">Lastname</label>
<div class="col-sm-10"><input type="text" class="form-control" name="user_lastname" value="<?php echo check_param($lastname); ?>"/></div>
</div>
<div class="form-group"><label class="col-sm-2 control-label">Phone</label>
<div class="col-sm-10"><input type="text" class="form-control" name="user_mobile" value="<?php echo check_param($mobile); ?>"/></div>
</div>
<div class="form-group"><label class="col-sm-2 control-label" for="birthday">Birthday
</label>
<div class="col-sm-10"><input id="birthday" type="text" class="form-control" name="user_birthday"></div>
</div>
<div class="form-group"><label class="col-sm-2 control-label">Manager</label>
<div class="col-sm-10"><select class="form-control m-b" name="manager_id">
<?php foreach ($managers_list as $managers_n) { ?>
<option <?php if ($managers_n['id'] == $managerid) {
echo 'selected';
} ?>
value="<?php echo $managers_n['id']; ?>"> <?php echo $managers_n['name']; ?></option>;
<?php }
?>
</select>
</div>
</div>
<input type="submit" name="edit-profile" class="btn btn-block btn-w-m btn-success"
value="Edit profile">
</form>
我負載曲線數據提交後編輯:
$update_result = $user->updateUser($_POST['user_id'],$_POST['user_firstname'],$_POST['user_lastname'],$_POST['user_mobile'],$_POST['user_birthday'],$_POST['manager_id']);
if($update_result){
echo 'Profile Edited';
}
只顯示消息資料編輯,但必須刷新頁面更新數據 我必須再次提取查詢更新值?還是有更好的辦法?
謝謝,我想到了阿賈克斯,但我必須爲AJAX創建一個句柄頁面上,可以不用處理頁面使用了Ajax這個網頁? – lock
這將是最好創建一個單獨的「頁面」(被稱爲:通話中)確實。您可以處理信息,然後將其回顯到頁面中。也許看看一些關於做Ajax調用的教程。 – cpalinckx
如果這個答案幫助你,woudl你介意接受它作爲正確答案?謝謝 :) – cpalinckx