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我有一個表格,從MySQL表中提取數據到一個窗體,每一行都有一個菜單來選擇一個值,我想更新MySQL與選擇每行的每個值時'應用全部「按鈕被點擊,但不起作用。,這裏是我的代碼。更新列表值的MySQL表
<td><form id="main" name="main" method="post" action="setProjectStatus.php" onsubmit="return validateMain();">
<table width="100%" cellspacing="1" cellpadding="1">
<tr>
<td width="35%" rowspan="3"><img src="../img/project.jpg" alt="Comp Sci Stud" width="325" height="199" border="2" /></td>
<td width="65%" height="42" colspan="2"><table width="94%" cellpadding="1" cellspacing="1" class="main_table">
<tr class="table_title">
<td width="100%" class="table_title">Set Project Status. </td>
</tr>
<tr>
<td height="26"> </td>
</tr>
<tr>
<td height="26"><table width="100%" cellspacing="1" cellpadding="1">
<tr class="table_head">
<td width="2%" height="35"><div align="center"></div></td>
<td width="26%" height="35"><div align="center">Student Name</div></td>
<td colspan="2"><div align="center">Project</div></td>
<td width="19%"><div align="center">Status</div></td>
</tr>
<?php
session_start();
$username = $_SESSION['username'];
require_once("mysqlConnect.php");
//
$sql="SELECT * FROM spms_Student";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
echo "There are $count projects to be undertaken.";
while($rows=mysql_fetch_array($result)){
//
$query = "SELECT name FROM spms_systemUser WHERE userId = '".$rows[0]."'";
$result1 = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result1);
$name = $row[0];
?>
<tr>
<td height="25" align="center"> </td>
<td align="center"><?php echo $name; ?></td>
<td colspan="2" align="center"><?php echo $rows[1]; ?></td>
<td align="center"><label>
<select name="select" class="form_field_100px_select">
<option value="Pending" selected="selected">Pending</option>
<option value="Approved">Approved</option>
<option value="Disapproved">Disapproved</option>
</select>
</label></td>
</tr>
<?php
}
?>
<tr class="pager_bg">
<td height="35"> </td>
<td> </td>
<td width="37%" align="right"><input name="done" type="button" id="done" value="Done" onclick="window.location='../coordinatorMenu.html'" /></td>
<td width="16%"><label>
<input name="approveAll" type="submit" id="approveAll" value="Approve All" />
</label></td>
<td><input name="apply" type="submit" id="apply" value="Apply To All" /></td>
</tr>
<?php
mysql_close();
?>
</table></td>
</tr>
</table></td>
</tr>
<tr>
<td colspan="2"> </td>
</tr>
<tr>
<td colspan="2"><label></label> <label></label></td>
</tr>
</table>
</form></td>
和setProjectStatus.php中的代碼是什麼? – Elen 2012-03-26 14:47:05
這將有助於很多..我們不能真正幫助你,因爲它似乎所有的魔術都發生在另一頁上;) – snaderss 2012-03-26 14:51:25
這個頁面正在調用自己,,只有這個代碼在頂部...... if isset($ _ POST ['approveAll'])){ \t //連接並選擇一個數據庫 \t require_once(「mysqlConnect.php」); \t \t $ sql =「UPDATE tablename SET projectStatus ='Approved'」; \t mysql_query($ sql); } – user1293274 2012-03-26 15:35:25