首先,我有兩個文本字段,第一個是登錄,第二個是密碼和一個登錄按鈕。我正在使用通過push segue連接到另一個視圖控制器的故事板和登錄按鈕。 這次在我的項目中工作,將用戶名和密碼放入文本字段,並在移動另一個視圖後選擇登錄按鈕。我輸入了錯誤的密碼登錄仍然是移動另一個視圖。我認爲某個地方的情況是錯誤的。 請幫助我到底該怎麼做。謝謝如何成功登錄並使用php web服務移動到另一個視圖
我按照這個教程Dipin Krishna Tutorial
我的代碼是
- (IBAction)loginac:(id)sender {
NSInteger success = 0;
@try {
if([[self.txfld text] isEqualToString:@""] || [[self.tx1 text] isEqualToString:@""]) {
[self alertStatus:@"Please enter Email and Password" :@"Sign in Failed!" :0];
} else {
NSString *post =[[NSString alloc] initWithFormat:@"username=%@&password=%@",[self.txfld text],[self.tx1 text]];
NSLog(@"PostData: %@",post);
NSURL *url=[NSURL URLWithString:@"https://dipinkrishna.com/jsonlogin.php"];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%lu", (unsigned long)[postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];
//[NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[url host]];
NSError *error = [[NSError alloc] init];
NSHTTPURLResponse *response = nil;
NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSLog(@"Response code: %ld", (long)[response statusCode]);
if ([response statusCode] >= 200 && [response statusCode] < 300)
{
NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
NSLog(@"Response ==> %@", responseData);
NSError *error = nil;
NSDictionary *jsonData = [NSJSONSerialization
JSONObjectWithData:urlData
options:NSJSONReadingMutableContainers
error:&error];
success = [jsonData[@"success"] integerValue];
NSLog(@"Success: %ld",(long)success);
if(success == 1)
{
NSLog(@"Login SUCCESS");
} else {
NSString *error_msg = (NSString *) jsonData[@"error_message"];
[self alertStatus:error_msg :@"Sign in Failed!" :0];
}
} else {
//if (error) NSLog(@"Error: %@", error);
[self alertStatus:@"Connection Failed" :@"Sign in Failed!" :0];
}
}
}
@catch (NSException * e) {
NSLog(@"Exception: %@", e);
[self alertStatus:@"Sign in Failed." :@"Error!" :0];
}
if (success) {
[self performSegueWithIdentifier:@"login_success" sender:self];
}
}
- (void) alertStatus:(NSString *)msg :(NSString *)title :(int) tag
{
UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:title
message:msg
delegate:self
cancelButtonTitle:@"Ok"
otherButtonTitles:nil, nil];
alertView.tag = tag;
[alertView show];
}
你在corect方式需要一個小的修改 –
@ Anbu.Karthik感謝重播,哪裏需要一個小的修改 –
我張貼的答案檢查一次 –