2016-03-03 134 views
0

比方說,我有一個正在運行的服務的API,響應就像一個網址:REST API服務:如何通過PHP curl正確調用它?

http://example.com/param/1 

這是對GET和POST動詞擔任。 Param = 1是參數

如何正確執行curl請求以傳遞參數(POST)?

如果我瀏覽:http://example.com/param/1 我會回來預期的響應(GET)

但如果我這樣做,這是行不通的:

$service_url = 'http://example.com/'; 
$curl = curl_init($service_url); 
$curl_post_data = array('param'=>1); 

curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($curl, CURLOPT_POST, true); 
curl_setopt($curl, CURLOPT_POSTFIELDS, $curl_post_data); 
$curl_response = curl_exec($curl); 
if ($curl_response === false) { 
    $info = curl_getinfo($curl); 
    curl_close($curl); 
    die('error occured during curl exec. Additional info: ' . var_export($info)); 
} 
curl_close($curl); 
$decoded = json_decode($curl_response); 
if (isset($decoded->response->status) && $decoded->response->status == 'ERROR') { 
    die('error occured: ' . $decoded->response->errormessage); 
} 
echo 'response ok!'; 
var_export($decoded->response); 

即使改變它像如下因素將無法正常工作:

$service_url = 'http://example.com/param/1'; 
$curl = curl_init($service_url); 

curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($curl, CURLOPT_POST, true); 
$curl_response = curl_exec($curl); 
if ($curl_response === false) { 
    $info = curl_getinfo($curl); 
    curl_close($curl); 
    die('error occured during curl exec. Additional info: ' . var_export($info)); 
} 
curl_close($curl); 
$decoded = json_decode($curl_response); 
if (isset($decoded->response->status) && $decoded->response->status == 'ERROR') { 
    die('error occured: ' . $decoded->response->errormessage); 
} 
echo 'response ok!'; 
var_export($decoded->response); 

這不是工作:但我想它仍然是一個GET

$service_url = 'http://example.com/param/1'; 
$curl = curl_init($service_url); 
$curl_response = curl_exec($curl); 
if ($curl_response === false) { 
    $info = curl_getinfo($curl); 
    curl_close($curl); 
    die('error occured during curl exec. Additional info: ' . var_export($info)); 
} 
curl_close($curl); 
$decoded = json_decode($curl_response); 
if (isset($decoded->response->status) && $decoded->response->status == 'ERROR') { 
    die('error occured: ' . $decoded->response->errormessage); 
} 
echo 'response ok!'; 
var_export($decoded->response); 

回答

0
$service_url = 'http://example.com/param/1';  
$ch = curl_init($service_url); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); 
curl_setopt($ch, CURLOPT_POSTFIELDS, "param1=value1&param2=value2&.."); 
$response = curl_exec($ch); 
curl_close($ch); 
+0

不,不是。 param = 1是要傳遞的參數...您列出的後置字段不是必需的(param1,param2 ....) – koalaok