SELECT
C.TABLE_SCHEMA+'.'+ C.TABLE_NAME as TableName,
C.COLUMN_NAME as ColumnName,
C.DATA_TYPE as ColumnDataType,
C.CHARACTER_MAXIMUM_LENGTH as ColumnDataTypeLength,
(CASE
WHEN K.CONSTRAINT_NAME like 'PK_%' then 'PRIMARYKEY'
WHEN K.CONSTRAINT_NAME like 'FK_%' then 'FOREIGNKEY'
ELSE NULL
END) as [Keys],
(SELECT
i.[type_desc]
FROM
[sys].[indexes] AS i
INNER JOIN
[sys].[index_columns] AS ic
ON i.[object_id] = ic.[object_id]
AND i.index_id = ic.index_id
INNER JOIN
[sys].[columns] co
ON ic.column_id = co.column_id
AND ic.[object_id] = co.[object_id]
WHERE
i.[object_id] = OBJECT_ID(C.TABLE_SCHEMA+'.'+ C.TABLE_NAME)
AND co.name=C.COLUMN_NAME
) AS [Indexes]
FROM
INFORMATION_SCHEMA.COLUMNS C LEFT JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE K
ON C.COLUMN_NAME=k.COLUMN_NAME
AND C.TABLE_NAME=K.TABLE_NAME
WHERE C.TABLE_SCHEMA+'.'+ C.TABLE_NAME [email protected]
ORDER BY C.ORDINAL_POSITION ASC
很高興你能夠解決它自己的表或視圖的列的元數據,並公佈了答案其他面臨類似問題的人。請考慮接受您的答案,方法是點擊答案左側的灰色複選圖標。 – DhruvJoshi