SELECT INTO advanced

Question

我在我的數據庫中有很多表，我正在收集下面的代碼的計算值，並希望將這些值插入到其他表中。我使用SELECT INTO方法，但數據庫告訴我「關鍵字INTO行附近的語法不正確......」。我相信有一些我失蹤，但不知道在哪裏。代碼看起來很好。這是我的代碼。任何幫助，將不勝感激。

SELECT (second.[cdate]=@enddate) AS 'Date', first.[machine_no] AS 'No', 
tbl_machines.[manufacturer] As 'Manufacturer', 
tbl_machines.[type] As 'Machine Type',tbl_machines.[game_name] AS 'Game Name', 
tbl_machines.[accounting_denomination] AS 'Denom', 
(second.[turnover])-(first.[turnover]) AS 'Turnover', 
(second.[total win])-(first.[total win]) AS 'Total win', 
(second.[games played])-(first.[games played]) AS 'Games Played', 
(second.[Bill in])-(first.[Bill in]) AS 'Bill In', 
(second.[credit in])-(first.[credit in]) AS 'Credit IN', 
(second.[cancel credit])-(first.[cancel credit]) AS 'Cancel Credit', 
tbl_rate.[euro] AS 'euro rate', 
tbl_rate.[dollar] AS 'dollar rate' 
INTO tbl_daily 
FROM tbl.meter first,tbl.machines,tbl_rate 
INNER JOIN tbl_meter second ON first.[Machine_No] = second.[Machine_No] 
AND 
tbl_machines.[local_no]=first.[machine_no] 
WHERE first.[cDate] = @StartDate 
AND second.[cDate] = @EndDate 
AND tbl_rate.[cdate]=@enddate; 

---

好吧，我用INSERT INTO語法，一切都很順利，但現在我有問題，日期時間。當我使用下面的sql命令時，我收到錯誤，它說「無法將數據類型位轉換爲日期時間」我試過Martin的轉換方法，但它是一樣的。

我的代碼是

INSERT INTO tbl_daily SELECT tbl_machines.[ID] AS 'ID', (second.[cdate]=@enddate) AS 'CDate', first.[machine_no] AS 'No', 
tbl_machines.[manufacturer] As 'Manufacturer', 
tbl_machines.[type] As 'MachineType', 
tbl_machines.[game_name] AS 'GameName', 
tbl_machines.[accounting_denomination] AS 'Denom', 
(second.[turnover]-first.[turnover]) AS 'Turnover', 
(second.[total win]-first.[total win]) AS 'Totalwin', 
(second.[games played]-first.[games played]) AS 'GamesPlayed', 
(second.[credit in]-first.[credit in]) AS 'CreditIN', 
(second.[Bill in]-first.[Bill in]) AS 'BillIn', 
(second.[cancel credit]-first.[cancel credit]) AS 'CancelCredit', 
tbl_rate.[euro] AS 'eurorate', 
tbl_rate.[dollar] AS 'dollarrate' 
FROM tbl_meter first,tbl_machines,tbl_rate 
INNER JOIN tbl_meter second ON first.[Machine_No] = second.[Machine_No] AND tbl_machines.[local_no]=first.[machine_no] 
WHERE first.[cDate] = @StartDate AND second.[cDate] = @EndDate AND tbl_rate.[cdate]=@enddate; 

Answer 1

注：以下答案寫假設的SQL Server。我刪除它收到VistaDB的澄清時，但在再次反刪除它reading是

VistaDB的，可以看作是一個子集，Microsoft SQL Server的T-SQL的 。所有 我們的語法在SQL Server中， 支持，但周圍沒有

在這種情況下，其他的方式，我認爲它是安全地說，如果是在SQL Server無效，將在VistaDB的無效也？這在SQL Server中是無效的語法。

SELECT (second.[cdate]=@enddate) AS 'Date' 

這段代碼的目的是什麼？它是否意味着一個布爾值？ （即當列匹配變量時返回true）。如果是這樣的話，在SQL Server中最接近於此。

SELECT CAST((CASE WHEN second.[cdate]=@enddate THEN 1 ELSE 0 END) AS BIT) AS 'Date' 

編輯從我看到它旨在

SELECT @enddate AS 'Date' 

此外，我沒有看到SELECT ... INTOlisted as a VistaDB command這裏的意見。它是否受到支持？

Answer 2

如果您使用的是SQL Server，Insert Into更適用於插入到即時創建的表中。這是一個好的做法，但如果表已經存在，那麼我會用這個：

INSERT INTO table (column1, columns2, ...) 
SELECT 
    Value1, 
    Value2, 
    ... 
FROM ...