2013-03-08 72 views
0

我已經在我的文件下面的查詢:多左聯接和ORDER BY

function getItems($ShowFeatured,$OrderBy,$Order,$amountShow,$ShowPropertyID) 

{   
switch($OrderBy) { 
case 0 : 
$OrderBy = 'p.id'; 
break; 
case 1 : 
$OrderBy = 'p.name'; 
break; 
case 2 : 
$OrderBy = 'p.price'; 
break; 
case 3 : 
$OrderBy = 'p.hits'; 
break; 
case 4 : 
$OrderBy = 'p.refresh_time'; 
break; 
} 
switch($Order) { 
case 0 : 
$Order = 'ASC'; 
break; 
case 1 : 
$Order = 'DESC'; 
break; 
} 
if($ShowPropertyID){$where= 'WHERE p.id IN ('.$ShowPropertyID.')';}else{$where=  'WHERE p.published = 1 ';} 
    if($ShowFeatured){$sqlFeatured= ' AND p.featured = 1';} 
    $db = &JFactory::getDBO();  
    $query = 'SELECT p.*, i.name as imagename,c.id as key1,c.name as name_category,t.id as key5,t.name as name_type,cy.id as key2,cy.name as name_country,s.id as key3,s.name as name_state,l.id as key4,l.name as name_locality,' 
      . ' CASE WHEN CHAR_LENGTH(p.alias) THEN CONCAT_WS(":", p.id, p.alias) ELSE p.id END as Pslug,' 
    . ' CASE WHEN CHAR_LENGTH(c.alias) THEN CONCAT_WS(":", c.id, c.alias) ELSE c.id END as Cslug,' 
    . ' CASE WHEN CHAR_LENGTH(cy.alias) THEN CONCAT_WS(":", cy.id, cy.alias) ELSE cy.id END as CYslug,' 
    . ' CASE WHEN CHAR_LENGTH(s.alias) THEN CONCAT_WS(":", s.id, s.alias) ELSE s.id END as Sslug,'  
    . ' CASE WHEN CHAR_LENGTH(l.alias) THEN CONCAT_WS(":", l.id, l.alias) ELSE l.id END as Lslug, ' 
    . ' CASE WHEN CHAR_LENGTH(t.alias) THEN CONCAT_WS(":", t.id, t.alias) ELSE t.id END as Tslug ' 
      . ' FROM #__properties_products AS p ' 
      . ' LEFT JOIN #__properties_country AS cy ON cy.id = p.cyid '    
      . ' LEFT JOIN #__properties_state AS s ON s.id = p.sid ' 
      . ' LEFT JOIN #__properties_locality AS l ON l.id = p.lid ' 
      . ' LEFT JOIN #__properties_category AS c ON c.id = p.cid ' 
      . ' LEFT JOIN #__properties_type AS t ON t.id = p.type ' 
      . ' LEFT JOIN #__properties_images AS i ON p.id = i.parent ' 
      . $where     
      . $sqlFeatured 
      . ' GROUP BY p.id ' 
      . ' ORDER BY '.$OrderBy.' '.$Order 
      . ' LIMIT '.$amountShow; 

    $db->setQuery($query); 
    $items = $db->loadObjectList(); 



    // $items = ($items = $db->loadObjectList())?$items:array(); 
//echo str_replace('#_','jos',$query); 


    return $items; 

部分獲得的圖像如下:

. ' LEFT JOIN #__properties_images AS i ON p.id = i.parent ' 

這個查詢訂單通過i.parent圖像 - 圖像我得到我不喜歡。在我的數據庫中,我有行i.ordering - 是否有可能通過i.ordering在上面的查詢上訂購圖像?

謝謝。

+0

,而不是使用MAX MIN該代碼似乎需要一個參數的順序,其中沒有一個是對的i.parent列。如果你願意,可以相對容易地向SWITCH語句添加額外的選項以通過i.ordering命令。 – Kickstart 2013-03-08 09:04:38

+0

不,圖像只是一個片段 - 如果我將i.parent放入swistch選項,它只會重新排序來自數據庫的結果,但圖片仍然相同。問題是我有多個圖像表... – user1810168 2013-03-08 09:26:43

+0

啊,對。有多個圖像,但你只想要最新/最重要的一個返回。認爲你需要爲這些圖像選擇一個子選項。 – Kickstart 2013-03-08 09:28:43

回答

0

爲你這樣的事情查詢我認爲會做你想做的。

$query = 'SELECT p.*, i.name as imagename,c.id as key1,c.name as name_category,t.id as key5,t.name as name_type,cy.id as key2,cy.name as name_country,s.id as key3,s.name as name_state,l.id as key4,l.name as name_locality,' 
      . ' CASE WHEN CHAR_LENGTH(p.alias) THEN CONCAT_WS(":", p.id, p.alias) ELSE p.id END as Pslug,' 
    . ' CASE WHEN CHAR_LENGTH(c.alias) THEN CONCAT_WS(":", c.id, c.alias) ELSE c.id END as Cslug,' 
    . ' CASE WHEN CHAR_LENGTH(cy.alias) THEN CONCAT_WS(":", cy.id, cy.alias) ELSE cy.id END as CYslug,' 
    . ' CASE WHEN CHAR_LENGTH(s.alias) THEN CONCAT_WS(":", s.id, s.alias) ELSE s.id END as Sslug,'  
    . ' CASE WHEN CHAR_LENGTH(l.alias) THEN CONCAT_WS(":", l.id, l.alias) ELSE l.id END as Lslug, ' 
    . ' CASE WHEN CHAR_LENGTH(t.alias) THEN CONCAT_WS(":", t.id, t.alias) ELSE t.id END as Tslug ' 
      . ' FROM #__properties_products AS p ' 
      . ' LEFT JOIN #__properties_country AS cy ON cy.id = p.cyid '    
      . ' LEFT JOIN #__properties_state AS s ON s.id = p.sid ' 
      . ' LEFT JOIN #__properties_locality AS l ON l.id = p.lid ' 
      . ' LEFT JOIN #__properties_category AS c ON c.id = p.cid ' 
      . ' LEFT JOIN #__properties_type AS t ON t.id = p.type ' 
      . ' LEFT JOIN (SELECT parent, MAX(ordering) AS MostImportant FROM #__properties_images GROUP BY parent) x ON p.id = x.parent ' 
     . ' LEFT JOIN #__properties_images AS i ON x.parent = i.parent AND x.MostImportant = i.ordering ' 
      . $where     
      . $sqlFeatured 
      . ' GROUP BY p.id ' 
      . ' ORDER BY '.$OrderBy.' '.$Order 
      . ' LIMIT '.$amountShow; 

您可能要取決於哪種方式排序工作

+0

這不起作用......與p.id沒有聯繫... – user1810168 2013-03-08 10:56:29

+0

哪裏? P.id用於連接以與原始查詢相同的方式獲取所需的圖像,並使用該屬性中的x.parent id(應該是p.id)來加入以獲取實際圖像的詳細信息 – Kickstart 2013-03-08 11:00:34