爲什麼我不能在react-router 4.x中嵌套Route組件？

Question

如何在世界上使用react-router，特別是版本4.x中的嵌套路由？在以前的版本以下行之有效...

<Route path='/stuff' component={Stuff}> 
    <Route path='/stuff/a' component={StuffA} /> 
</Route> 

升級到4.x的拋出以下警告...

警告：你不應該使用<路線>組件和<路線孩子>在同一條路線上; <路線兒童>將被忽略

什麼在這裏發生了什麼？我搜索了the docs數小時，無法成功獲取嵌套路線。如何使用<Route>組件將其路由嵌套在react-router v4中？我的簡單示例如何轉換爲v4.x API合規性以嵌套路由？

Answer 1

忘記你對React Router < v4的瞭解。你通過嵌套<Routes>嵌套路線。檢查this example。具體檢查一下主題組件。您不需要預先聲明路由，而是在組件呈現時動態地聲明路由。

import React from 'react' 
import { 
    BrowserRouter as Router, 
    Route, 
    Link 
} from 'react-router-dom' 

const BasicExample =() => (
    <Router> 
    <div> 
     <ul> 
     <li><Link to="/">Home</Link></li> 
     <li><Link to="/about">About</Link></li> 
     <li><Link to="/topics">Topics</Link></li> 
     </ul> 

     <hr/> 

     <Route exact path="/" component={Home}/> 
     <Route path="/about" component={About}/> 
     <Route path="/topics" component={Topics}/> 
    </div> 
    </Router> 
) 

const Home =() => (
    <div> 
    <h2>Home</h2> 
    </div> 
) 

const About =() => (
    <div> 
    <h2>About</h2> 
    </div> 
) 

const Topics = ({ match }) => (
    <div> 
    <h2>Topics</h2> 
    <ul> 
     <li> 
     <Link to={`${match.url}/rendering`}> 
      Rendering with React 
     </Link> 
     </li> 
     <li> 
     <Link to={`${match.url}/components`}> 
      Components 
     </Link> 
     </li> 
     <li> 
     <Link to={`${match.url}/props-v-state`}> 
      Props v. State 
     </Link> 
     </li> 
    </ul> 

    {/* NESTED ROUTES */} 
    <Route path={`${match.url}/:topicId`} component={Topic}/> 
    <Route exact path={match.url} render={() => (
     <h3>Please select a topic.</h3> 
    )}/> 
    </div> 
) 

const Topic = ({ match }) => (
    <div> 
    <h3>{match.params.topicId}</h3> 
    </div> 
) 

export default BasicExample