將1d數組與用戶輸入進行比較？

Question

我正在寫一個測驗程序。我有一個來自文本文件的正確答案的1維數組，我必須將其與users_guess進行比較以檢查他的猜測是否正確。我必須吐出6個隨機問題。

string questions[50]; // 50 questions 
char answers[50]; // 50 correct answers 
int i = 0; 
char user_guess; 

int rand_index = rand() % 10; //generate random number 

for (i=0; i<6; i++)  //loop for 6 questions 
{  
cout << questions[rand_index] << endl; 
questions[rand_index] = answers[] // i need help. how do i compare the arrays? 
cin >> user_guess; 
    if (user_guess != answers[]) // if he's wrong 
    { 
    cout << "sorry. try again" << endl; 
    cout << questions[rand_index] << endl; // 2nd chance 
    cin >> user_guess; 
     if (user_guess!= answers[]) // wrong again 
     { 
     cout << "you lose.game over." << endl; //game over 
     break; // does this cancel the game all together? 

     } 
     else 
     { 
     cout << "good job!" << endl; 
     i++; // on to the next round 
     } 
    } 
    else 
    { 
    cout << "good job!" << endl; 
    i++; // on to the next round 
    } 
} 

我的麻煩是越來越多的問題與答案數組掛鉤。另外，如果他錯了兩次，程序結束。你們都在想什麼？

Answer 1

Here's a hint: 

// ... 
{ 
    const string &the_question = questions[rand_index]; 
    const char &the_answer = answers[rand_index]; // using a const char & 
               // is a deliberate pedantism 


    cout << the_question << endl; 
    char user_guess; 
    cin >> user_guess; 
    if (the_answer != user_guess) { 
    ... 
    } 

注意：你在一個好的工作後再增加一次，然後再次在for循環中，所以你會以兩個數來計算。