如何添加到foreach循環中的多維數組上的新索引？

Question

地獄再次，我想知道如何在foreach循環內添加數據到新的數組索引？

代碼我有ATM是，

// Connect to the database to gather all data pertaiing to the link in question 
$assoResult = mysql_query("SELECT * FROM associate_users"); 
while ($assoRow = mysql_fetch_field($assoResult)) { 
    $resultArray[] = $assoRow->name; 
} 

// Connect to the database to gather all data pertaiing to the link in question 
$assoResult2 = mysql_query("SELECT * FROM associate_users WHERE id='$getID'"); 
while ($assoRow2 = mysql_fetch_object($assoResult2)) { 

    foreach ($resultArray as $row) { 
     $array = array(array(1 => $assoRow2->$row, 2 => $row,),); 
     echo "<br />"; print_r($array); 
    }    
} 

下面是來自於 「回聲 」BR />輸出的數據「;的print_r（$陣列）;」線。

============================================== ===================

Array ([0] => Array ([1] => 1 [2] => id)) 
Array ([0] => Array ([1] => Bob[2] => contactName)) 
Array ([0] => Array ([1] => Bob's Tyres [2] => company)) 
Array ([0] => Array ([1] => XXXXXXXXXXXXXX [2] => address1)) 
Array ([0] => Array ([1] => XXXXXXXXXXXXXX [2] => address2)) 
Array ([0] => Array ([1] => XXXXXXXXX [2] => address3)) 
Array ([0] => Array ([1] => XXXXXX [2] => postcode)) 

正如你可以看到陣列正在創建一個新的一遍又一遍，我需要的是對上述數據每個循環增加一維索引鍵，所以它看起來像...

============================= ====================================

Array ([0] => Array ([1] => 1 [2] => id)) 
Array ([1] => Array ([1] => Bob[2] => contactName)) 
Array ([2] => Array ([1] => Bob's Tyres [2] => company)) 
Array ([3] => Array ([1] => XXXXXXXXXXXXXX [2] => address1)) 
Array ([4] => Array ([1] => XXXXXXXXXXXXXX [2] => address2)) 
Array ([5] => Array ([1] => XXXXXXXXX [2] => address3)) 
Array ([6] => Array ([1] => XXXXXX [2] => postcode)) 

在此先感謝您我沒有辦法讓這個工作和絕望。

丹。

Answer 1

更改分配代碼的一部分值

$count=0; 
    foreach ($resultArray as $row) { 
      $array[$count][1] = $assoRow2->$row 
      $array[$count][2]=$row; 
      $count++; 
      echo "<br />"; print_r($array); 
     } 

Answer 2

//extra code.declaring array 
$array = array(); 
while ($assoRow2 = mysql_fetch_object($assoResult2)) { 
    foreach ($resultArray as $row) { 
// 1st parameter is the array name, here array name is array .give gd name according to use 
     array_push($array,array(1 => $assoRow2->$row, 2 => $row,)); 
     echo "<br />"; print_r($array); 
    }    
} 

Answer 3

這段代碼可以讓你你要的輸出不低效率使用兩個查詢：

// Connect to the database to gather all data pertaining to the link in question 
$result = mysql_query("SELECT * FROM associate_users WHERE id=" . (int)$getID); 

$resultArray = array(); 
$resultCount = 0; 
$row = mysql_fetch_assoc($result); 

$count = 0; 
foreach ($row as $key => $value) { 
    $temp = array(); 
    $temp[$count] = array(1 => $value, 2 => $key); 
    $count++; 

    echo "<br />"; print_r($temp); 
} 

爲什麼你要它像這，我不知道。