如何合併兩個詞典與Python中的字典？

Question

下面是來自類似輸入的大文件的示例輸入。

{ 
    "V-Su7890": [ 
     [ 
      { 
       "url": "www.talent.com", 
       "tid": "V-Su7890", 
       "id": "58ff787ffbad487b2c", 
       "company_name": "Talent Ltd" 
      } 
     ], 
     [ 
      { 
       "socials": ["facebook", "linkedin", "twitter"], 
       "title": "title of the pag", 
       "contact": ["+9563802140"], 
       "email": "email_id1" 
      }, 
      { 
       "socials": ["facebook", "twitter", "linkedin"], 
       "title": "next title of the page", 
       "contact": ["+919765983442"], 
       "email": "email_id2" 
      } 
     ] 
    ] 
} 

我不得不當前詞典的第二列表的所有分字典合併成一個字典沒有重複的值，然後存入字典作爲一個值鍵「V-Su7890」。

所需的輸出是：

{ 
    "V-Su7890": [ 
     [ 
      { 
       "url": "www.talent.com", 
       "tid": "V-Su7890", 
       "id": "58ff787ffbad487b2c", 
       "company_name": "Talent Ltd" 
      } 
     ], 
     [ 
      { 
       "socials": ["facebook", "linkedin", "twitter"], 
       "title": ["title of the pag", "next title of the page"], 
       "contact": ["+9563802140", "+919765983442"], 
       "email": ["email_id","email_id2"] 
      } 
     ] 
    ] 
} 

請幫助我瞭解和解決這個問題。

Answer 1

您可以使用setdefault()以默認值插入關鍵（在這裏你可以使用空表），並extend列表，如果新項目不存在。

for k,v in a.items(): 
    tmp={} 
    for i in v[1]: 
     for k1,v2 in i.items(): 
      if isinstance(v2,list): 
       tmp.setdefault(k1,[]).extend(i for i in v2 if i not in tmp[k1]) 
      else: 
       tmp.setdefault(k1,[]).append(v2) 
    a[k]=[v[0],[tmp]] 
print(a) 

結果：

{ 
    'V-Su7890': [ 
    ... 
    [ 
     { 
     'contact': ['+9563802140','+919765983442'], 
     'socials': ['facebook','linkedin','twitter'], 
     'email': ['email_id1','email_id2'], 
     'title': ['title of the pag','next title of the page'] 
     } 
    ] 
    ] 
} 

Answer 2

假設你存儲完整dict在一個變量V.我們爲socials，title等存儲在一組值，以避免出現重複的值。稍後，我們會將這些設置轉換爲列表。這裏的解決方案：

V = k["V-Su7890"][1] 
new_dict = {} 

for v in V: 
    for key, value in v.iteritems(): 
     if not new_dict.get(key, None): 
      new_dict[key] = set() 

     if isinstance(value, list): 
      for val in value: 
       new_dict[key].add(val) 
     else: 
      new_dict[key].add(value) 

# Converting the sets to list 
for key, value in new_dict.iteritems(): 
    new_dict[key] = list(value) 

k["V-Su7890"][1] = [new_dict]