我有兩個代碼,都生成折線圖。但是,第一個不使用mysql數據源,它使用隨機數學生成的數據點。但它使用刷新間隔,因此是活的。如何正確傳輸Javascript代碼?
第二個代碼實際上使用的是mysql數據源,並將數據顯示在我的數據庫的折線圖中。但它不是實時的,因爲它沒有刷新間隔功能。
我試圖將第一個代碼的refresh-Interval/chart-update代碼部分傳遞給我的第二個不活動但使用實際數據源的代碼。
這裏是我住的代碼,用隨機數據點:
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.4/jquery.min.js">`
<script type="text/javascript">
window.onload = function() {
var dps = []; // dataPoints
var chart = new CanvasJS.Chart("chartContainer2",{
title :{
text: "Patient #01"
},
data: [{
type: "line",
dataPoints: dps
}]
});
var xVal = 0;
var yVal = 100;
var updateInterval = 20;
var dataLength = 500; // number of dataPoints visible at any point
var updateChart = function (count) {
count = count || 1;
// count is number of times loop runs to generate random dataPoints.
for (var j = 0; j < count; j++) {
yVal = yVal + Math.round(5 + Math.random() *(-5-5));
dps.push({
x: xVal,
y: yVal
});
xVal++;
};
if (dps.length > dataLength)
{
dps.shift();
}
chart.render();
};
// generates first set of dataPoints
updateChart(dataLength);
// update chart after specified time.
setInterval(function(){updateChart()}, updateInterval);
}
</script>
這是我的靜線圖的代碼(非實時),但是使用真實的數據源:
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.4/jquery.min.js">`
</script>
<script type="text/javascript">
$().ready(function() {
$.getJSON("arduino_data.php", function (result) {
var dataPoints = [];
for (var i = 0; i <= result.length - 1; i++) {
dataPoints.push({ x: Number(result[i].x), y: Number(result[i].y) });
}
var chart = new CanvasJS.Chart("chartContainer",{
title :{
text: "Patient #01"
},
data: [{
type: "line",
dataPoints: dataPoints
}]
});
chart.render();
});
});
</script>
<script type="text/javascript" src="canvasjs.min.js"></script>
這是我到目前爲止所嘗試過的:
<html>
<head>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.4/jquery.min.js"> </script>
<script type="text/javascript">
$().ready(function() {
$.getJSON("arduino_data.php", function (result) {
var chart = new CanvasJS.Chart("chartContainer",{
title :{
text: "Patient #01"
},
data: [{
type: "line",
dataPoints: dataPoints
}]
});
var dataPoints = [];
var updateInterval = 20;
var dataLength = 500; // number of dataPoints visible at any point
var updateChart = function (count) {
count = count || 1;
for (var i = 0; i <= result.length - 1; i++) {
dataPoints.push({ x: Number(result[i].x), y: Number(result[i].y) });
};
}
if (dataPoints.length > dataLength)
{
dataPoints.shift();
}
chart.render();
)};
// generates first set of dataPoints
updateChart(dataLength);
// update chart after specified time.
setInterval(function(){updateChart()}, updateInterval);
}
</script>
<script type="text/javascript" src="canvasjs.min.js"></script>
</head>
<body>
<div id="chartContainer" style="height: 300px; width:100%;">
</div>
</body>
</html>
但它口口聲聲說
Unexpected token ')' at line 42
chart.render();
)};
我很尷尬,但我不能找到解決辦法,由於所有的手鐲/ parenthesizes。我已經嘗試了一切。與)和沒有}但似乎沒有提供。
如果解決了,代碼的年代位置會好嗎?
編輯:第一個問題解決了,新的問題:JS定位
<!DOCTYPE HTML>
<html>
<head>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.4/jquery.min.js"> </script>
<script type="text/javascript">
$().ready(function() {
$.getJSON("arduino_data.php", function (result) {
var chart = new CanvasJS.Chart("chartContainer",{
title :{
text: "Patient #01"
},
data: [{
type: "line",
dataPoints: dataPoints
}]
});
var dataPoints = [];
var updateInterval = 20;
var dataLength = 500; // number of dataPoints visible at any point
var updateChart = function (count) {
count = count || 1;
for (var i = 0; i <= result.length - 1; i++) {
dataPoints.push({ x: Number(result[i].x), y: Number(result[i].y) });
};
}
if (dataPoints.length > dataLength)
{
dataPoints.shift();
}
chart.render();
});
// generates first set of dataPoints
updateChart(dataLength);
// update chart after specified time.
setInterval(updateChart, updateInterval);
});
</script>
<script type="text/javascript" src="canvasjs.min.js"></script>
</head>
<body>
<div id="chartContainer" style="height: 300px; width:100%;">
</div>
</body>
</html>
輸出:
Can't find variable: updateChart
你說你不能找到行42?如果你正確縮進你的JS,即使在記事本中,這些錯誤也是微不足道的。 –
對不起,我應該更清楚,第42行是在:chart.render(); \t)};無論我在那裏改變,它都不起作用 –
'chart.render(); )};'last應該是'});'和'setInterval();'應該有相同的'});' –