×2陣列在一個第一陣列retrive兩個值

Question

First_mutableArray是1,2,3,4,5,6
Second_MutableArray是2,4,6,8,0,12

如何獲得這樣

First_mutableArray輸出1,2,3,4,5,6,8,0,12？

Answer 1

有序版本：

NSMutableOrderedSet *first = [NSMutableOrderedSet orderedSetWithObjects:@"1",@"2",@"3",@"4",@"5",@"6",nil]; 
    NSOrderedSet *second = [NSOrderedSet orderedSetWithObjects:@"2",@"4",@"6",@"8",@"0",@"12",nil]; 
    [first unionOrderedSet:second]; 

Variab第一個第一個將包含結果。

Answer 2

嘗試：

NSMutableArray *first=[NSMutableArray arrayWithArray:@[@"1",@"2",@"3",@"4",@"5",@"6"]]; 
NSMutableArray *second=[NSMutableArray arrayWithArray:@[@"2",@"4",@"6",@"8",@"0",@"12"]]; 

for (id obj in second) { 
    if (![first containsObject:obj]) { 
     [first addObject:obj]; 
    } 
} 
NSLog(@"%@",first); 

---

編輯：

NSMutableArray *first=[NSMutableArray arrayWithArray:@[@"1",@"2",@"3",@"4",@"5",@"6"]]; 
NSMutableArray *second=[NSMutableArray arrayWithArray:@[@"2",@"4",@"6",@"8",@"0",@"12"]]; 


NSMutableOrderedSet *firstSet=[NSMutableOrderedSet orderedSetWithArray:first]; 
NSOrderedSet *secondSet=[NSOrderedSet orderedSetWithArray:second]; 

[firstSet unionOrderedSet:secondSet]; 
first=[[firstSet array] mutableCopy]; 

NSLog(@"%@",first); 

* 幸得馬克Kryzhanouski

Answer 3

結合這兩個陣列和combinedArray 2刪除重複使用下面的代碼。

NSMutableArray* combinedArray = [NSMutableArray arrayWithArray:firstArray]; 
[combinedArray addObjectsFromArray: secondArray]; 
NSMutableArray *myUniqueArray = [NSMutableArray array]; 

for (id obj in combinedArray) { 
    if (![myUniqueArray containsObject:obj]) { 
     [myUniqueArray addObject:obj]; 
    } 
} 

Answer 4

使用此代碼

NSMutableArray *array = [[NSMutableArray alloc]initWithObjects:@"1",@"2",@"3",@"4",@"5",@"6", nil]; 
    NSMutableArray *array1 = [[NSMutableArray alloc]initWithObjects:@"2",@"4",@"6",@"8",@"0",@"12", nil]; 
    for(int i = 0;i<array1.count;i++) 
    { 
     NSString *str = [array1 objectAtIndex:i]; 
     if (![array containsObject:str]) 
     { 
      [array addObject: str]; 
     }else 
     { 
      NSLog(@"contins"); 
     } 
    } 
    NSLog(@"%@",array); 

Answer 5

您可以使用NSMutableSet做這個東西：

NSMutableSet *firstSet = [NSMutableSet setWithArray:First_mutableArray]; 
NSMutableSet *secondSet = [NSMutableSet setWithArray:Second_MutableArray]; 
[firstSet unionSet:secondSet]; 
NSArray *uniqueArray = [firstSet allObjects]; 

Answer 6

在這裏你走了。使用NSSet將比迭代每個數組並添加不匹配的對象更好的性能。

NSArray *arr1 = @[@1,@2,@3,@4,@5,@6]; 
NSArray *arr2 = @[@2,@4,@6,@8,@0,@12]; 

NSMutableSet *set = [[NSMutableSet alloc] initWithArray:arr1]; 
[set addObjectsFromArray:arr2]; 

// Unsorted 
NSLog(@"set = %@", [set description]); 

// Sorted 
NSSortDescriptor *sort = [NSSortDescriptor sortDescriptorWithKey:@"self" ascending:YES]; 
NSArray *sortedArray = [set sortedArrayUsingDescriptors:[NSArray arrayWithObject:sort]]; 
NSLog(@"sortedArray = %@", [sortedArray description]); 

Answer 7

嘗試以下之一：

NSMutableArray *first=[NSMutableArray arrayWithArray:@[@"1",@"2",@"3",@"4",@"5",@"6"]]; 
NSMutableArray *second=[NSMutableArray arrayWithArray:@[@"2",@"4",@"6",@"8",@"0",@"12"]]; 

NSMutableSet *firstSet = [NSMutableSet setWithArray:first]; 
NSMutableSet *secondSet = [NSMutableSet setWithArray:second]; 
[firstSet unionSet:secondSet]; 
NSArray *uniqueArray = [firstSet allObjects];