只顯示小時和分鐘？

Question

如何只顯示小時和分鐘在外地，如果我讓他們單獨

[SELECT 
    D.numOperador, 
    SUM(DATEDIFF(MINUTE, D.FechaSalida, D.FechaLlegada))/60 AS \[Horas\] , 
    SUM(DATEDIFF(MINUTE, D.FechaSalida, D.FechaLlegada)) % 60 AS \[Minutos\] 

    FROM 
    trkOperadores O 
    INNER JOIN trfDespacho D ON O.NumOperador = D.numOperador 
WHERE 
    O.cveTipoOperador = 2 
    AND O.NumOperador = 900200 
    AND D.FechaSalida>='2017-03-10 00:00:00.000' AND D.FechaLlegada<='2017-03-11 00:00:00.000' 
GROUP BY 
    D.NumOperador; 
GO] 

Time

Answer 1

如果你只是想在結果中加入小時，MNS在一起，串聯兩者：

SELECT 
D.numOperador, 
    (cast (SUM(DATEDIFF(MINUTE, D.FechaSalida, D.FechaLlegada))/60 as varchar) 
+ 
cast (SUM(DATEDIFF(MINUTE, D.FechaSalida, D.FechaLlegada)) % 60 AS varchar) ) as time 

FROM 
trkOperadores O 
INNER JOIN trfDespacho D ON O.NumOperador = D.numOperador 
WHERE 
O.cveTipoOperador = 2 
AND O.NumOperador = 900200 
AND D.FechaSalida>='2017-03-10 00:00:00.000' AND D.FechaLlegada<='2017-03-11 00:00:00.000' 
GROUP BY 
D.NumOperador; 
GO] 

Answer 2

我假設你想要這樣的東西。

DECLARE @D1 DATETIME = '20170401' 
DECLARE @D2 DATETIME = '20170402 00:05:00' 

SELECT RIGHT('00' + CAST(DATEDIFF(MINUTE, @D1, @D2) /60 AS VARCHAR(2)) , 2) + ':' + RIGHT('00' + CAST(DATEDIFF(MINUTE, @D1, @D2) % 60 AS VARCHAR(2)) , 2) 

-- 24:05 

Answer 3

SELECT 
    D.numOperador, 
    SUM(DATEDIFF(MINUTE, D.FechaSalida, D.FechaLlegada))/60 AS [Horas] , 
    SUM(DATEDIFF(MINUTE, D.FechaSalida, D.FechaLlegada)) % 60 AS [Minutos] 

    CONVERT(VARCHAR(10),CAST(CAST (D.FechaSalida AS FLOAT) - CAST (D.FechaLlegada AS FLOAT)/86400. AS DATETIME),108) --86400 equal 1 day 

    FROM 
    trkOperadores O  INNER JOIN trfDespacho D 
    ON O.NumOperador = D.numOperador 
WHERE 
    O.cveTipoOperador = 2 
    AND O.NumOperador = 900200 
    AND D.FechaSalida>='2017-03-10 00:00:00.000' AND D.FechaLlegada<='2017-03-11 00:00:00.000' 
GROUP BY 
    D.NumOperador; 
GO