獲取有關VARCHAR SQL左側

Question

我有一個nvarchar列含有「約翰·史密斯」

我想將其劃分爲「約翰·史密斯」和「」

任何想法如何做的第一空間那？我嘗試了長度，但它沒有考慮取左側位

Answer 1

該函數返回的字符串長度的2倍，其中包括空間，對於一個nvarchar：

DATALENGTH(@variable) 

所以LEFT(@variable, LEN(@variable))和RIGHT(@variable, DATALENGTH(@variable)/2 - LEN(@variable))應該工作。

我從你的使用nvarchar，這是SQL Server的假設......在例如

Answer 2

戰利品：

DECLARE @js NVARCHAR(MAX) = N'John Smith ' 
SELECT CASE WHEN RIGHT(@js, 1) = NCHAR(32) THEN SUBSTRING(@js, 1, DATALENGTH(@js)/2-1) ELSE @js END JohnSmith, 
CASE WHEN RIGHT(@js, 1) = NCHAR(32) THEN NCHAR(32) ELSE N'' END Space 

Answer 3

內的查詢，請嘗試：

... 
rtrim(MyColumn) NoTrailingSpaces, 
right(MyColumn, len(MyColumn) - len(rtrim(MyColumn))) TrailingSpacesOnly, 
... 

Answer 4

- 從數據中刪除填充。更換填充字符如果你喜歡

DECLARE @js varchar(50) 
DECLARE @M INT 
DECLARE @I INT 
DECLARE @C CHAR 
DECLARE @WORD VARCHAR(50) 
DECLARE @LPAD VARCHAR(50) 
DECLARE @RPAD VARCHAR(50) 
DECLARE @LEFT_PADDING_CHARACTER CHAR 
DECLARE @RIGHT_PADDING_CHARACTER CHAR 
DECLARE @TERMINATOR_CHARACTER CHAR 

-- INIT THE STRINGS 
SELECT @LPAD = '' 
SELECT @RPAD = '' 
SELECT @WORD = '' 
SELECT @LEFT_PADDING_CHARACTER = ' ' 
SELECT @RIGHT_PADDING_CHARACTER = ' ' 
SELECT @TERMINATOR_CHARACTER = '~' 
SELECT @js = ' John Smith ' 
SELECT @js = @js + @TERMINATOR_CHARACTER -- ADD TO CALC THE LENGTH 
SELECT @I = 1        -- FIRST CHARACTER 
SELECT @M = LEN(@JS)      -- LAST CHARACTER 

WHILE @I < @M    -- PARSE OUT THE LEFT PADDING 
BEGIN 
    SELECT @C = SUBSTRING(@js, @I, 1) 
    IF @C = @LEFT_PADDING_CHARACTER SELECT @LPAD = @LPAD + @C 
    ELSE GOTO PARSERIGHTPADDING 
    SELECT @I = @I + 1 
END 

PARSERIGHTPADDING: 
SELECT @I = LEN(@JS) -1  -- POINT TO THE LAST CHAR 
SELECT @M = 1   -- POINT TO THE FIRST CHAR 
SELECT @js = LTRIM(@JS)  -- TRIM OFF THE LEFT PADDING 
SELECT @js = REPLACE(@js, @TERMINATOR_CHARACTER, '' -- TRIM OFF THE TERMINATOR 

WHILE @M < @I    -- PARSE OUT THE RIGHT PADDING 
BEGIN  
    SELECT @C = SUBSTRING(@js, @I, 1) 
    IF @C = @RIGHT_PADDING_CHARACTER SELECT @RPAD = @RPAD + @C 
    ELSE GOTO REMOVEPADDINGS 
    SELECT @I = @I - 1 
END 

REMOVEPADDINGS: 
SELECT @WORD = LTRIM(RTRIM(@js)) 

-- SELECT THE RESULTS TO VIEW THEM @LPAD AND @RPAD SHOULD BE BLANK 
SELECT @LPAD [LPAD], @WORD [WORD], @RPAD [RPAD]