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如何在XSLT中從父節點2的子節點訪問父節點1的子節點?從XSLT中的節點的子節點訪問另一個節點的子節點
<Test>
<SOLUTIONS>
<SOLUTION>
<OBSERVATIONS>
<OBSERVATION Key = "1ASED">A1</OBSERVATION>
<OBSERVATION Key = "2DFED">A2</OBSERVATION>
<OBSERVATION Key = "3DGEE">A3</OBSERVATION>
</OBSERVATIONS>
<ITRs>
<ITR Key = "ASE1">P1</ITR>
<ITR Key = "GGEE1">P2</ITR>
<ITR Key = "GERFECE1">P3</ITR>
</ITRs>
</SOLUTION>
<SOLUTION>
<OBSERVATIONS>
<OBSERVATION Key = "ABCD">A1</OBSERVATION>
<OBSERVATION Key = "EFGH">A2</OBSERVATION>
<OBSERVATION Key = "IJKL">A3</OBSERVATION>
</OBSERVATIONS>
...
</SOLUTION>
</SOLUTIONS>
</Test>
對於每個ITR,我需要打印觀察結果。對於裏面的第一個ITR,我必須把這個鍵連接到觀察鍵上。所以,共顯示9條記錄。
我的XSLT是
<xsl:for-each select="/Test/SOLUTIONS/SOLUTION">
<xsl:for-each select="ITRs/ITR">
<xsl:variable name="Key_ITRPS" select="@Key"/>
<xsl:for-each select="/Test/SOLUTIONS/SOLUTION/OBSERVATIONS/OBSERVATION">
<xsl:variable name="srcKey_A" select="@Key"/>
<xsl:element name="Relationship">
<xsl:attribute name="RelCommonKey">
<xsl:value-of select="concat($Key_ITRPS,$srcKey_A)"/>
</xsl:attribute>
</xsl:element>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
我需要的輸出是
RelCommonKey
ASE11ASED
ASE12DFED
ASE13DGEE
GGEE11ASED
GGEE12DFED
GGEE13DGEE
GERFECE11ASED
GERFECE12DFED
GERFECE13DGEE
我面對這裏的問題是隨着上述數據,我是晚上注意到在第二個觀察重點太。
的ITR鍵「ASE1」也鏈接到「ABCD‘EFGH’,‘IJKL’也。請幫我在限制數據上面顯示。
:)謝謝科林·我想我錯過了../../OBSERVATIONS/OBSERVATION感謝您的幫助+1答案:) – Ramm 2011-05-02 06:44:39
沒有問題的話,。這回答你的問題,你應該點擊'剔'符號將它標記爲答案。 – ColinE 2011-05-02 06:46:06