如何轉換2014年10月4點13分24秒到2014-10-10T04:13:24 + 00:00在PHP或MySQL如何日期時間轉換爲unix命令日期
上面提到的日期是在站點地圖
對於參考校驗Q: How do I compute lastmod date? (Sitemaps.org FAQ)
代碼的XML格式,我曾嘗試:
echo "GIVEN DATE ".$timestamp = "2014-10-10 04:13:24";
echo "<br>";
$year = date('Y',strtotime($timestamp)).";
$month = date('m',strtotime($timestamp)).";
$day = date('d',strtotime($timestamp))."";
echo '<br>';
$hour = date('H',strtotime($timestamp))."";
$minutes = date('i',strtotime($timestamp))."";
$seconds = date('s',strtotime($timestamp))."<br>";
$gmktime= gmmktime($hour,$minutes,$seconds,$month,$day,$year)."<br>";
echo "output date".$isodate = date('c', $gmktime);
上述輸出轉換是否正確?
**OUTPUT** GIVEN DATE : 2014-10-10 04:13:24 output date : 2014-10-10T06:13:24+02:00
哪裏有區別? – 2014-10-10 07:22:54
兩個日期都是一樣的。你忘了什麼嗎? – Jerodev 2014-10-10 07:23:37
對不起,請立即檢查 – 2014-10-10 07:24:45