檢查日期在MATLAB中是否有效

Question

爲了不誤導任何人，這是一個硬件問題，我正試圖完成並需要一點幫助。問題本身是不言自明的。我必須編寫一個函數，在其中輸入一個字符串'Month Day，Year'並讓它告訴我它是否有效（true或false語句）。我已經爲幾乎所有的事情工作，除了現在似乎沒有認識到我可能的日子的限制。

function[valid] = isValidDate(str) 
[date, year] = strtok(str, ','); %Should give me the date and year 
[~, year2] = strtok(year, ' '); 
[month, day] = strtok(date, ' '); %Should give me month and the day 
day = round(day); 
if length(date) < 6 
valid = false; 
elseif month(1) == upper(month(1)) 
    valid = true; 
elseif length(date) >= 12 
    valid = false; 
    end 
if year2 >= 0 
    valid = true; 
else 
    valid = false; 
end 
leapyear = mod(year, 400) == 0 | (mod(year, 4) == 0 ~= mod(year, 100) == 0); 

switch month 
    case {'September','April','June','November'} 

day <= 30; 
    valid = true; 
    case {'February'} 
     if leapyear 
      day <= 29; 
      valid = true; 
     else 
      day <= 28; 
      valid = true; 
     end 
    case {'January', 'March', 'May', 'July', 'August', 'October', 'December'} 
     days <= 31; 
     valid = true; 
otherwise 
    valid = false; 

end 
end 

所以基本上

valid4 = isValidDate('December 29.9, -1005.7') 
valid = false 

注：會有一天後，沒有後綴。我現在唯一的問題是，我的功能沒有意識到我的日子受到限制。它喜歡想'2014年2月30日'是可能的

Answer 1

代碼

function[valid] = isValidDate(str) 

[date1, year1] = strtok(str, ','); %Should give me the date and year 
[month1, day1] = strtok(date1, ' '); %Should give me month and the day 

%// 1. Take care of bad month strings 
all_months = {'January', 'February','March', 'April', 'May','June',... 
    'July', 'August', 'September','October','November' 'December'} ; 
if ~ismember(cellstr(month1),all_months) 
    valid = false; 
    return; 
end 

%// 2. Take care of negative or fraction days 
day1 = day1(isstrprop(day1,'digit')); %// Take care of suffixes after day string 
num_day = str2double(day1); 
if round(num_day)~=num_day || num_day<1 
    valid = false; 
    return; 
end 

%// 3. Take care of fraction or negative years 
num_year = str2double(strtok(year1,',')); 
if round(num_year)~=num_year || num_year<0 
    valid = false; 
    return; 
end 

lpyr =mod(num_year, 400) == 0 | (mod(num_year, 4) == 0 ~= mod(num_year, 100) == 0); 

switch month1 
    case {'September','April','June','November'} 
     if num_day > 30 
      valid = false; 
      return; 
     end 
    case {'February'} 
     if (lpyr && num_day > 29) | (~lpyr && num_day > 28) 
      valid = false; 
      return; 
     end 
    case {'January', 'March', 'May', 'July', 'August', 'October', 'December'} 
     if num_day > 31; 
      valid = false; 
      return; 
     end 
end 
valid = true; %// We made it through! 

return; 

---

如果你希望有一個緊湊的代碼 -

function valid = isValidDate(str) 

[date1, year1] = strtok(str, ','); %Should give me the date and year 
[month1, day1] = strtok(date1, ' '); %Should give me month and the day 

%// 1. Take care of bad month strings 
all_months = {'January', 'February','March', 'April', 'May','June',... 
    'July', 'August', 'September','October','November' 'December'} ; 
valid_month = ismember(cellstr(month1),all_months); 

%// 2. Take care of negative or fraction days 
day1 = day1(isstrprop(day1,'digit')); %// Take care of suffixes after day string 
num_day = str2double(day1); 
valid_day = round(num_day)==num_day && num_day>=1; 

%// 3. Take care of fraction or negative years 
num_year = str2double(strtok(year1,',')); 
valid_year = round(num_year)==num_year && num_year>=0; 

%// 4. Take care of valid days based on leap year and days in a month limits 
lpyr = mod(num_year, 400) == 0 | (mod(num_year, 4) == 0 ~= mod(num_year, 100) == 0); 
valid_leapyear = true; 
switch month1 
    case {'September','April','June','November'} 
     valid_leapyear = num_day<=30; 
    case {'February'} 
     valid_leapyear = ~((lpyr && num_day>29) || (~lpyr && num_day>28)); 
    case {'January', 'March', 'May', 'July', 'August', 'October', 'December'} 
     valid_leapyear = num_day<=31; 
end 
valid = valid_year & valid_month & valid_day & valid_leapyear; 
return; 

Answer 2

我做了一些簡單的功能，使用matlab中的java接口。希望它會有用。

function [valid] = isValidDate(dateStr) 
    valid = true; 
    dateFormat = java.text.SimpleDateFormat('MMM dd, yyyy'); 
    dateFormat.setLenient(false); 
    try 
     dateFormat.parse(dateStr); 
     valid = true; 
    catch err 
     valid = false; 
    end  
end 

例子：

isValidDate('December 21, 1934');  % gives 1 
isValidDate('December 29.9, -1005.7'); % gives 0