無法通過while循環在sql中獲取計數值？

我需要獲得發送消息數的用戶。無法通過while循環在sql中獲取計數值？

$userlist = mysql_query("select count(distinct m.subject) as msgcnt, u.name from message as m, message_users as mu, users as u where m.owner_id = u.id and m.id=mu.msg_id and mu.user_id='$u_id'group by name") or mysql_error(); 
     while($row=mysql_fetch_array($userlist)) 
     {    
      echo $row['name']."<br />"; 
     }

如何通過while循環利用得到的計數值..

來源

2013-03-04 AndRaGhu

$用戶列表=請求mysql_query（「SELECT COUNT（DISTINCT m.subject）作爲msgcnt，u.name從消息爲m，message_users爲μ，用戶爲u，其中m.owner_id = u.id和m.id = mu.msg_id和mu.user_id ='$ u_id'group by name「）或mysql_error（）; 查詢問題可能會給空間mu.user_id ='$ _ id'組 – 2013-03-04 06:34:41

你已經是存儲別名msgcnt所述計，簡單地echo它。

while($row=mysql_fetch_assoc($userlist)) 
     {    
      echo $row['name']." : ".$row['msgcnt']."<br />"; 
     }

來源

2013-03-04 06:34:56

+1爲正確的答案和涼爽的T恤 – silly 2013-03-04 06:36:43

大聲笑，感謝您的評論:) – 2013-03-04 06:38:11

echo $row['msgcnt'].'<br/>';

來源

2013-03-04 06:34:33 Achrome

使用mysql_fetch_assoc得到關聯數組！

$userlist = mysql_query("select count(distinct m.subject) as msgcnt, u.name from message as m, message_users as mu, users as u where m.owner_id = u.id and m.id=mu.msg_id and mu.user_id='$u_id'group by name") or mysql_error(); 
while($row=mysql_fetch_assoc($userlist)) {    
     echo $row['name']."<br />";   
     echo $row['msgcnt']."<br />"; 
    }

來源

2013-03-04 06:36:08 silly

使用msgcnt時指定別名作爲msgcnt

echo $row['msgcnt']."<br />";

來源

2013-03-04 06:36:36

無法通過while循環在sql中獲取計數值？

回答

相關問題