添加嘗試並抓住現有程序

Question

良好的夜晚， 在一個有點巨大的屁股泡菜，可以使用一點點的幫助。所以我寫了這個C＃控制檯應用程序，它使用Selenium打開一個網頁，登錄，做一些事情，然後提交一個表單並註銷網站。現在我有一個for循環做100次。現在很少有它可能會打嗝並引發異常，導致頁面加載速度不夠快或什麼。我認爲使用try/catch可能會很好，但是一旦catch捕捉到異常，但是我希望它重做它所在並繼續的那個循環數。因此，例如，如果我在100的迭代66上，並且它引發了一個異常，導致頁面加載速度不夠快，或者頁面上出現了該鏈接的錯誤，我需要它來捕獲它，記錄它，然後重新啓動數字66再次。下面是我的一些原始代碼和我已經得到的另一部分。

using System; 
using System.Collections.Generic; 
using System.Text; 
using OpenQA.Selenium; 
using OpenQA.Selenium.Firefox; 
using OpenQA.Selenium.Support.UI; 
using System.Threading; 
using System.IO; 

namespace SeleniumTest 
{ 
class Program 
{ 
    static void Main(string[] args) 
    { 
      for (Int64 i = 1; i < 100; i++) 
      { 
       DateTime time; 
       time = DateTime.Now; 
       StreamWriter tw = new StreamWriter(@"C:\folder\file.txt", true); 
       IWebDriver driver = new FirefoxDriver(); 
       tw.WriteLine("Staring test," + time); 
       driver.Navigate().GoToUrl("http://site.com"); 
       driver.FindElement(By.Name("username")).Clear(); 
       driver.FindElement(By.Name("username")).SendKeys("username"); 
       driver.FindElement(By.Name("password")).Clear(); 
       driver.FindElement(By.Name("password")).SendKeys("password"); 
       driver.FindElement(By.CssSelector("input.ui-standard-button")).Click(); 
       driver.FindElement(By.LinkText("page")).Click(); 
       driver.FindElement(By.LinkText("page")).Click(); 
       Thread.Sleep(5000); 
       //Do awesome stuff 
       DateTime time1; 
       time1 = DateTime.Now; 
       driver.FindElement(By.CssSelector("div.Parameters")).Click(); 
       driver.FindElement(By.Name("submit")).Click(); 
       driver.FindElement(By.LinkText("Logoff")).Click(); 
       driver.Quit(); 
       tw.WriteLine("Stopping Test Successfully," + time1); 
       tw.Flush(); 
       tw.Close(); 
       Thread.Sleep(10000); 
      } 
     } 
    } 
} 


using System; 
using System.Collections.Generic; 
using System.Text; 
using OpenQA.Selenium; 
using OpenQA.Selenium.Firefox; 
using OpenQA.Selenium.Support.UI; 
using System.Threading; 
using System.IO; 

namespace SeleniumTest 
{ 
class Program 
{ 
    static void Main(string[] args) 
    { 
     try 
      { 
      for (Int64 i = 1; i < 100; i++) 
      { 
       DateTime time; 
       time = DateTime.Now; 
       StreamWriter tw = new StreamWriter(@"C:\folder\file.txt", true); 
       IWebDriver driver = new FirefoxDriver(); 
       tw.WriteLine("Staring test," + time); 
       driver.Navigate().GoToUrl("http://site.com"); 
       driver.FindElement(By.Name("username")).Clear(); 
       driver.FindElement(By.Name("username")).SendKeys("username"); 
       driver.FindElement(By.Name("password")).Clear(); 
       driver.FindElement(By.Name("password")).SendKeys("password"); 
       driver.FindElement(By.CssSelector("input.ui-standard-button")).Click(); 
       driver.FindElement(By.LinkText("page")).Click(); 
       driver.FindElement(By.LinkText("page")).Click(); 
       Thread.Sleep(5000); 
       //Do awesome stuff 
       DateTime time1; 
       time1 = DateTime.Now; 
       driver.FindElement(By.CssSelector("div.Parameters")).Click(); 
       driver.FindElement(By.Name("submit")).Click(); 
       driver.FindElement(By.LinkText("Logoff")).Click(); 
       driver.Quit(); 
       tw.WriteLine("Stopping Test Successfully," + time1); 
       tw.Flush(); 
       tw.Close(); 
       Thread.Sleep(10000); 
      } 
     } 
     catch(Exception e) 
     { 
      StreamWriter tw = new StreamWriter(@"C:\folder\file.txt", true); 
      tw.WriteLine("Problem happened. Restarting test. Exception is :" + e); 
      //Line of code to restart test at number 66 which I don't know 
     } 
    } 
    } 
} 

Where //重啓66號測試的代碼行，我不知道我的知識是在哪裏結束，希望是別人在哪裏。任何指導你可以給予很大的和讚賞。

Answer 1

遇到異常時減少計數器應該這樣做。

for (Int64 i = 1; i < 100; i++) { 
    try { 
     //main code here 
    } catch (Exception ex) { 
     //logging here 
     i--; 
    } 
} 

Answer 2

我會嘗試找出爲什麼它的失敗，但如果這不是一種選擇，我會把它轉換成while循環與嘗試捕捉

int i = 100; 
    while(i > 0) 
    { 
     try 
    { 
    //Do your logic here 
     i-- 
    } 
     catch 
    { 
     //Log failure 
     }//Don't decrement in case of failure 
    } 

Answer 3

for (Int64 i = 1; i < 100; ++i) 
{ 
    for (;;) 
    { 
    try 
    { 
     //code here 
     break; 
    } 
    catch (Exception exc) 
    { 
     //log error 
    } 
    } 
}