微小的url正在停止工作

Question

如何讓這個函數工作，如果鏈接被縮短的小url或類似的東西？它似乎首先通過小型的網址服務器，從而導致谷歌相關的關鍵字不被讀取。

-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest{ NSRange nameRange = [[inRequest.URL absoluteString] rangeOfString:@"google" options:NSCaseInsensitiveSearch]; 

if(nameRange.location == NSNotFound) 
{ 
    [[UIApplication sharedApplication] openURL:[inRequest URL]]; 
    return NO; 
} 
return YES; 
} 

Answer 1

你爲什麼不嘗試刪除if (inType == UIWebViewNavigationTypeLinkClicked)狀態，這樣你就能夠趕上重定向保持在URL中。見下面的代碼。

-(BOOL) webView:(UIWebView *)inWeb shouldStartLoadWithRequest:(NSURLRequest *)inRequest navigationType:(UIWebViewNavigationType)inType { 
    if ([[inRequest.URL absoluteString] rangeOfString:@"google"].location==NSNotFound){ 
    [[UIApplication sharedApplication] openURL:[inRequest URL]]; 
     return NO; 
    } 
    return YES; 
} 

Answer 2

使用此

NSRange nameRange = [[inRequest.URL absoluteString] rangeOfString:@"google" options:NSCaseInsensitiveSearch]; 

      if(nameRange.location == NSNotFound) 
      { 
       [[UIApplication sharedApplication] openURL:[inRequest URL]]; 
       return NO; 
      }