SQL服務器搜索過程

Question

我試圖尋找一個表視圖中的所有地址，屬於某個郵政編碼列表（500層+郵編）

通過不同的搜索答案，我發現一些非常接近我在尋找的東西this StackPost

問題是我正在處理一個視圖（沒有全文搜索），而不是1對1的值。

我試圖做線沿線的東西：

set @sql = "SELECT * FROM viewTABLE 
      WHERE CONTAINS(Address, '"+replace(@list, ',', ' OR ')+"')" 

但上面提到不工作 - 我可以創建包含郵政編碼列表如果讓事情變得簡單的表格，但每欄'地址'必須與郵政編碼列表進行比較。

任何幫助非常感謝！

Answer 1

您可以修改現有的代碼，做這樣的事情與LIKE聲明：

set @sql=" 
    SELECT * 
     FROM viewTABLE 
    WHERE Address LIKE '%"+replace(@list, ",", "%' OR Address LIKE '%")+"%'" 

這將產生@sql這樣的：

SELECT * 
    FROM viewTABLE 
WHERE Address LIKE '%12345%' OR Address LIKE '%22345%' OR Address Like '%55314%' 
     -- etc. 

但是它會更容易，如果郵編名單在一張桌子上：

SELECT * 
    FROM viewTABLE v 
WHERE EXISTS 
    (SELECT * FROM zipCodeList z 
    WHERE v.Address LIKE '%'+z.ZipCode+'%') 

Answer 2

這不是答案，但這開始幫助您瞭解我的想法，幫助您解決問題。我設法隔離地址列開頭的數字值。如果你隔離了最後的字符，那麼你就在路上。

DECLARE @Customer TABLE 
    (
     NewPK INT IDENTITY(1, 1) , 
     CustomerAddress NVARCHAR(MAX) NOT NULL 
    ) 
INSERT INTO @Customer 
     (CustomerAddress 
     ) 
VALUES ('10 Fraley St # C, Kane, PA 16735' 
     ) 
INSERT INTO @Customer 
     (CustomerAddress 
     ) 
VALUES ('5611 Market St, Maru, PA 500' 
     ) 
INSERT INTO @Customer 
     (CustomerAddress 
     ) 
VALUES ('5644 N County Road 400 N, Scipio, IN 47273' 
     ) 
INSERT INTO @Customer 
     (CustomerAddress 
     ) 
VALUES ('79 Fraley St # A, Kane, PA 500' 
     ) 
INSERT INTO @Customer 
     (CustomerAddress 
     ) 
VALUES ('5195 N Camelot Way, North Vernon, IN 47265' 
     ) 
INSERT INTO @Customer 
     (CustomerAddress 
     ) 
VALUES ('79 Fraley St # A, Kane, PA 16735' 
     ) 

SELECT CustomerAddress , 
     CASE WHEN PATINDEX('%[^0-9]%', CustomerAddress) > 0 
      THEN SUBSTRING(CustomerAddress, 
          PATINDEX('%[0-9]%', CustomerAddress), 
          CHARINDEX(' ', CustomerAddress + SPACE(1), 
             PATINDEX('%[0-9]%', CustomerAddress))) 
      ELSE CustomerAddress 
     END AS 'numeric' 
FROM @Customer