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我一直在嘗試使用AJAX/jQuery和Servlet來工作,並且我不斷收到語法錯誤,並且瀏覽器不顯示錯誤的位置。jQuery Ajax語法意想不到的令牌
這是代碼。
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
$(document).ready(function(){
$("#btnTest").click(function(){
var n = $("#vName").val();
$.get("TestServlet", (nm:n), function(responseText){
$("#textArea").text(responseText);
});
});
});
</script>
<body>
<h1>Hello World!</h1>
<input type="text" id="vName" value="" />
<input type="button" value="Ok" id="btnTest" />
<div id="textArea"></div>
</body>
然後在我的servlet我有這樣的;
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
PrintWriter out = response.getWriter();
try
{
String val = request.getParameter("mn");
String msg = "Hi User";
if(val!=null)
msg = "Hi, " + val;
response.setCharacterEncoding("UTF-8");
response.setContentType("text/plain");
response.getWriter().write(msg);
}
finally
{
out.close();
}
}
*「......和瀏覽器不顯示在錯誤在於」 *任何半體面的瀏覽器不僅會告訴你錯誤的位置,但給你一個*鏈接*在控制檯中導致錯誤的行。 – 2014-09-05 07:36:13