MySQL的桌到桌SQL

我想[更新]從交易表TRANSACTION_ID到CMAS表，但我失去了一些東西......不知道從哪裏引用CMAS表，所以它不會出錯#1054 - Unknown column 'cmas.property_id' in 'where clause'MySQL的桌到桌SQL

INSERT INTO `cmas` (`transaction_id`) 
SELECT `transaction_id` 
FROM `transactions` WHERE transactions.property_id = cmas.property_id // this bit is wrong!

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2012-01-11 Robert

既然你提到的評論的更新，這可能是你在找什麼：

UPDATE cmas, transactions 
SET cmas.transaction_id = transactions.transaction_id 
WHERE transactions.property_id = cmas.property_id

來源

2012-01-11 01:41:47 philofinfinitejest

這樣做！謝謝。 – Robert 2012-01-11 01:45:46

你應該把它改寫這樣的：

INSERT INTO `cmas` (`transaction_id`) 
SELECT `transaction_id` 
FROM `transactions` WHERE transactions.property_id IN (select property_id from `cmas`)

問題是存在於左部沒有選擇，所以表達「transactions.property_id = cmas.property_id」是meaninless，因爲沒有CMAS選擇完成。

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2012-01-11 01:16:19 kenota

這個運行，但犯規更新CMAS TRANSACTION_ID – Robert 2012-01-11 01:25:47

INSERT INTO cmas (transaction_id) 
SELECT transaction_id 
FROM transactions,cmas 
WHERE transactions.property_id = cmas.property_id

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2012-01-11 01:16:48 kba

此運行（當我修改SELECT來'交易.transaction_id'）但不更新cmas transaction_id – Robert 2012-01-11 01:25:14

，因爲這是比我的更好的解決方案，我會在這裏評論： – kenota 2012-01-11 01:27:25

它呢，它返回transaction_id – Robert 2012-01-11 01:33:12

MySQL的桌到桌SQL

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