PHP購物車顯示訂單

Question

海蘭，

我創建了培訓目的的PHP店。我希望用戶有可能查看他放置的最後一個訂單 - 但我有問題要意識到這一點。

我在我的數據庫這些表：

客戶（孩子姓名，地址，...）
產品（PID，PRODUCT_NAME，PRODUCT_DESCRIPTION，價格）
訂單 - > OID，孩子，支付，地址，狀態
order_detail - > OID，日期，PID，數量）

好吧，我創建了一個函數，其中一個查詢從數據庫中獲取的所需數據

function showOrder($kid) 
{ 
$db = database(); 
$orders = $db->query ("SELECT * FROM orders 
    INNER JOIN order_detail on orders.oid=order_detail.oid 
    INNER JOIN products on order_detail.pid = products.pid 
    WHERE kid='$kid' "); 

$orders = $orders->fetchAll(); 

$lastoid = 0; 
foreach($orders as $i){ 

    while($lastoid != $i['oid']) { 
     $lastoid = $i['oid']; 
     echo "Ordernr: ".$lastoid."<br/>"; 
     echo "Produktname: ".$i['product_name']."<br>"; 
     echo "Menge: ".$i['quantity']."<br/>"; 
     echo "Preis: ".$i['price']."<br/>"; 
     echo "Status: ".$i['status']."<br/>"; 
     echo "<br/><br/><hr/>";  
    } 
} 
} 

我想要做的：在一個表（ 列表中的單筆訂單 - > oderid |產品名稱|數量|價格|狀態） 如果訂單僅包含一種產品，但是如果訂單變得更大（2種產品），則僅顯示第一種產品。

$數據庫看起來是這樣的：

Array 
(
[0] => Array 
    (
     [oid] => 1 
     [0] => 1 
     [kid] => 1 
     [1] => 1 
     [2] => 1 
     [date] => 2012-04-17 
     [3] => 2012-04-17 
     [pid] => 1 
     [4] => 1 
     [quantity] => 2 
     [5] => 2 
     [payment] => Nachnahme 
     [6] => Nachnahme 
     [street] => teststraße 
     [7] => teststraße 
     [number] => 2 
     [8] => 2 
     [zip] => 2222 
     [9] => 2222 
     [city] => Teststadt 
     [10] => Teststadt 
     [status] => in Bearbeitung 
     [11] => in Bearbeitung 
     [12] => 1 
     [product_name] => Acer Laptop 
     [13] => Acer Laptop 
     [price] => 29.00 
     [14] => 29.00 
     [details] => blabla 
     [15] => blabla 
     [category] => Laptop 
     [16] => Laptop 
     [date_added] => 2012-04-05 
     [17] => 2012-04-05 
    ) 

[1] => Array 
    (
     [oid] => 1 
     [0] => 1 
     [kid] => 1 
     [1] => 1 
     [2] => 1 
     [date] => 2012-04-17 
     [3] => 2012-04-17 
     [pid] => 2 
     [4] => 2 
     [quantity] => 2 
     [5] => 2 
     [payment] => Nachnahme 
     [6] => Nachnahme 
     [street] => teststraße 
     [7] => teststraße 
     [number] => 2 
     [8] => 2 
     [zip] => 2222 
     [9] => 2222 
     [city] => Teststadt 
     [10] => Teststadt 
     [status] => in Bearbeitung 
     [11] => in Bearbeitung 
     [12] => 2 
     [product_name] => Grundig TV 
     [13] => Grundig TV 
     [price] => 22.00 
     [14] => 22.00 
     [details] => blabla 

     [15] => blabla 
     [category] => TV 
     [16] => TV 
     [date_added] => 2012-04-05 
     [17] => 2012-04-05 
    ) 

[2] => Array 
    (
     [oid] => 1 
     [0] => 1 
     [kid] => 1 
     [1] => 1 
     [2] => 1 
     [date] => 2012-04-17 
     [3] => 2012-04-17 
     [pid] => 7 
     [4] => 7 
     [quantity] => 1 
     [5] => 1 
     [payment] => Nachnahme 
     [6] => Nachnahme 
     [street] => teststraße 
     [7] => teststraße 
     [number] => 2 
     [8] => 2 
     [zip] => 2222 
     [9] => 2222 
     [city] => Teststadt 
     [10] => Teststadt 
     [status] => in Bearbeitung 
     [11] => in Bearbeitung 
     [12] => 7 
     [product_name] => Nokia Handy 
     [13] => Nokia Handy 
     [price] => 69.00 
     [14] => 69.00 
     [details] => blabla 
     [15] => blabla 
     [category] => Handy 
     [16] => Handy 
     [date_added] => 2012-04-06 
     [17] => 2012-04-06 
    ) 

[3] => Array 
    (
     [oid] => 2 
     [0] => 2 
     [kid] => 1 
     [1] => 1 
     [2] => 2 
     [date] => 2012-04-17 
     [3] => 2012-04-17 
     [pid] => 8 
     [4] => 8 
     [quantity] => 1 
     [5] => 1 
     [payment] => Vorauskasse 
     [6] => Vorauskasse 
     [street] => musterstraße 
     [7] => musterstraße 
     [number] => 1 
     [8] => 1 
     [zip] => 1111 
     [9] => 1111 
     [city] => stadt 
     [10] => stadt 
     [status] => in Bearbeitung 
     [11] => in Bearbeitung 
     [12] => 8 
     [product_name] => PC groß 
     [13] => PC groß 
     [price] => 66.00 
     [14] => 66.00 
     [details] => blabla 
     [15] => blabla 
     [category] => Computer 
     [16] => Computer 
     [date_added] => 2012-04-06 
     [17] => 2012-04-06 
    ) 
) 

Answer 1

問題是你是不是從產品表中選擇。您的選擇查詢只是orders.*，這只不過是orders table下的所有列。解決方案是將產品列添加到您的選擇查詢。我不是很清楚爲什麼你明確地使用內部連接，我的將是這樣的：

select orders.*, products.* from orders,order_detail,products where 
orders.oid=order_detail.oid and order_detail.pid=products.pid and orders.kid=1 

下面是結果我有：

| oid | kid | pid | product_name | 
| 1 | 1 | 1 | camera  | 
| 1 | 1 | 2 | pants  | 

Answer 2

你的代碼進入while循環用

$lastoid = 0; 

它將運行在第一個while循環，因爲$ lastoid不等於$ I [ 'OID']。一個是零，另一個是一個。在下一行中，將$ i ['oid']的值賦給$ lastoid。這使他們平等，你的while循環將停止。如果循環不會中斷，那麼您將擁有無盡的相同信息。在while循環有下一順序沒有提及。

更改像這樣

$lastoid = 1; 
foreach($orders as $key => $value){ 

    if($lastoid == $value[$key]['oid']) { 
     echo "Ordernr: ".$lastoid."<br/>"; 
     echo "Produktname: ".$i['product_name']."<br>"; 
     echo "Menge: ".$i['quantity']."<br/>"; 
     echo "Preis: ".$i['price']."<br/>"; 
     echo "Status: ".$i['status']."<br/>"; 
     echo "<br/><br/><hr/>";  
    } else { 
     $lastoid = $value[$key+1]['oid']; 
    } 
}