選擇一個RANDOM鍵，然後突破在HashMap中的迭代器/循環

Question

我想通過一個HashMap循環，這樣它應該選擇任何隨機的鍵，如果找到該鍵，它應該跳出循環並選擇與該KEY對應的值。

但不知何故此代碼不起作用，它只是選擇一個特定的值。請注意，它具有我編寫了下面IF語句的所有值和鍵。

下面是我的代碼

Iterator<Entry<String, Set<String>>> it = arg0.getSubstylearea().entrySet().iterator(); 

    A: while (it.hasNext()) { 
     Map.Entry<String, Set<String>> entry = (Map.Entry<String, Set<String>>) it.next(); 
     String key = entry.getKey(); 
     Set<String> temp = arg0.getSubstylearea().get(key); 

     if (key.equals("Eyes")) { 
      flatont.setStylearea1(key); 
      System.out.println("This Doesnt Print"); 
      for (String s : temp) { 

       flatont.setStylesubarea1(s); 

      } 
      break A; 
     } else if (key.equals("Face")) { 

      flatont.setStylearea1(key); 

      for (String s : temp) { 

       flatont.setStylesubarea1(s); 
      } 
      break A; 
     } else if (key.equals("Lips")) { 

      flatont.setStylearea1(key); 

      for (String s : temp) { 

       flatont.setStylesubarea1(s); 
      } 
      break A; 
     } 
} 

請幫我如何實現這一目標

Answer 1

我不完全明白你以後在做什麼，但試試這個：

Map<String, Set<String>> map = arg0.getSubstylearea() 
    int index = new Random().nextInt(map.size()); 
    int i = 0; 
    for (Map.Entry<String, Set<String>> entry : map.entrySet()) { 
     if (i++ < index) { 
      continue; 
     } 
     String key = entry.getKey(); 
     Set<String> temp = arg0.getSubstylearea().get(key); 

     if (key.equals("Eyes")) { 
      flatont.setStylearea1(key); 
      System.out.println("This Doesnt Print"); 
      for (String s : temp) { 

       flatont.setStylesubarea1(s); 

      } 
     } else if (key.equals("Face")) { 

      flatont.setStylearea1(key); 

      for (String s : temp) { 

       flatont.setStylesubarea1(s); 
      } 
     } else if (key.equals("Lips")) { 

      flatont.setStylearea1(key); 

      for (String s : temp) { 

       flatont.setStylesubarea1(s); 
      } 
     } else { 
      // Do something else 
     } 
     break; 
    } 

Answer 2

什麼簡單的continue：

while (it.hasNext()) { 
    Map.Entry<String, Set<String>> entry = (Map.Entry<String, Set<String>>) it.next(); 
    String key = entry.getKey(); 
    Set<String> temp = arg0.getSubstylearea().get(key); 

    if (key.equals("Eyes")) { 
     flatont.setStylearea1(key); 
     System.out.println("This Doesnt Print"); 
     for (String s : temp) { 

      flatont.setStylesubarea1(s); 

     } 
     continue; 
    } else if (key.equals("Face")) { 

     flatont.setStylearea1(key); 

     for (String s : temp) { 

      flatont.setStylesubarea1(s); 
     } 
     continue; 
    } else if (key.equals("Lips")) { 

     flatont.setStylearea1(key); 

     for (String s : temp) { 

      flatont.setStylesubarea1(s); 
     } 
     continue; 
    } 
} 

這woud仍然遍歷鍵即使一個已找到指定的密鑰。否則，做一個簡單的break：

while (it.hasNext()) { 
    Map.Entry<String, Set<String>> entry = (Map.Entry<String, Set<String>>) it.next(); 
    String key = entry.getKey(); 
    Set<String> temp = arg0.getSubstylearea().get(key); 

    if (key.equals("Eyes")) { 
     flatont.setStylearea1(key); 
     System.out.println("This Doesnt Print"); 
     for (String s : temp) { 

      flatont.setStylesubarea1(s); 

     } 
     break; 
    } else if ... etc