我有這個功能,可以根據你選擇看哪個掃描我的文件,並打印出一張預先指定的記錄:打印出從文件中的信息通過設計的另一個功能循環搜索的文件 - C++
void addressBook::showRecord(int pickNum) {
PEOPLE2 p;
ifstream indata("vectortest.dat", ios::binary);
if(!indata) {
cout << "Error opening file for reading " << endl;
exit(0);
}
indata.seekg(pickNum * sizeof(PEOPLE2));
indata.read(reinterpret_cast <char*> (&p), sizeof(PEOPLE2));
cout << p.fName2 << " " << p.lName2 << " " << p.Address2 << " " << endl;
}
所以你所要做的就是將showRecord放入main中,然後選擇你想打印的名字。說我想看看存儲的第二個名字,我會把在
newBook->showRecord(1);
這就是所有罰款的花花公子,和它的作品完美,但如果我想走得更遠一點什麼。所以我創建了另一個函數,它可以使用showRecord打印出存儲在我的文件中的地址簿中的所有名稱。我嘗試這樣做:
void addressBook::showAll() {
ifstream indata("vectortest.dat", ios::binary);
for(int i = 0; i < indata.end; i++) {
showRecord(i);
}
}
和它的作品,但只打印出這很難編碼到我一個人結構從以前分配的東西:
addressBook *newBook = addressBook::newbookInst();
PERSON me[] = {{"First" , "Last", "ADDRESS"}, {"John", "Doe", "1234"}};
newBook->addPerson(me[1]);
newBook->addPerson(me[0]);
這只是奇怪怎麼一回事,因爲當我進入文件本身,我可以看到所有添加的名稱。
那麼如何使用它,以便它實際上打印出文件中的所有內容,而不僅僅是永久存儲的兩個條目?
這是我addressbook.h和addressbook.cpp代碼的情況下,你需要一個更深入的瞭解怎麼回事...
\\ addressbook.h ////////
#ifndef _ADDRESSBOOK
#define _ADDRESSBOOK
#include <fstream>
#include <vector>
#include<string>
using std::string;
#include <iostream>
using namespace std;
using std::istream;
using std::ostream;
namespace CJ
{
const int MAXADDRESS =25;
struct PERSON
{
string fName;
string lName;
string Address;
};
struct PEOPLE2
{
char fName2[25];
char lName2[25];
char Address2[25];
};
class addressBook
{
private:
vector<PERSON> people;
int head;
int tail;
public:
addressBook();
addressBook(const PERSON &p);
addressBook(const PERSON p[], int size);
addressBook(char *fName, char *lName, char *address);
bool addPerson(const PERSON &p);
bool sortcomp(const PERSON& p1, const PERSON& p2);
bool getPerson(PERSON &p);
bool findPerson(const string& lastName, PERSON& p);
bool findPerson(const string& lastName, const string& firstName, PERSON& p);
void bubbleSort(int *array,int length);
void printBook();
void sort();
void waitKey();
static addressBook *newbookInst();
static addressBook *tempNew;
static PERSON *p();
static PERSON *temPerson;
void showRecord(int pickNum);
void writeRecord();
void showAll();
friend ostream &operator << (ostream &, addressBook &);
addressBook operator =(const string& str);
addressBook &operator +=(const PERSON &p);
addressBook operator [](int x);
};
}
#endif
\\ addressbook.cpp /////
#include <iostream>
#include <fstream>
#include <cstdlib>
#include <conio.h>
#include <string>
using std::string;
#include "addressBook.h"
#include "menu.h"
namespace CJ
{
addressBook::addressBook()
: head(0), tail(-1)
{
}
addressBook::addressBook(const PERSON &p)
: head(0), tail(-1)
{
addPerson(p);
}
addressBook::addressBook(const PERSON p[], int size)
: head(0), tail(-1)
{
for(int i = 0; i < size; i++)
addPerson(p[i]);
}
addressBook::addressBook(char *fName, char *lName, char *Address)
: head(0), tail(-1)
{
PERSON tmp;
tmp.fName = fName;
tmp.lName = lName;
tmp.Address = Address;
addPerson(tmp);
}
bool addressBook::addPerson(const PERSON &p)
{
people.push_back(p);
if(tail == -1)
tail++;
return true;
}
bool addressBook::getPerson(PERSON &p)
{
if(tail >=0)
{
if(tail >= people.size())
tail = 0;
p = people[tail];
tail++;
return true;
}
return false;
}
bool addressBook::findPerson(const string &lastName, PERSON &p)
{
for(size_t i = 0; i < people.size(); i++)
{
if(people[i].lName == lastName)
{
PERSON *p = addressBook::p();
*p = people[i];
return true;
}
}
return false;
}
bool addressBook::findPerson(const string &lastName, const string &firstName, PERSON &p)
{
for(size_t i = 0; i < people.size(); i++)
{
if(people[i].lName == lastName && people[i].fName == firstName)
{
PERSON *p = addressBook::p();
*p = people[i];
return true;
}
}
return false;
}
void addressBook::printBook()
{
for(size_t i = 0; i < people.size(); i++)
{
std::cout << people[i].fName << "\t" << people[i].lName << "\t" << people[i].Address << std::endl;
}
}
bool addressBook::sortcomp(const PERSON& p1, const PERSON& p2)
{
int result = (p1.lName.compare(p2.lName)) ;
if (result > 0)
return true ;
if (result < 0)
return false ;
return (p1.fName.compare(p2.fName)) > 0 ;
}
void addressBook::sort()
{
bool didSwap ;
do
{
didSwap = false ;
for (unsigned i=1; i<people.size(); ++i)
if (sortcomp(people[i-1], people[i]))
{
std::swap(people[i-1], people[i]) ;
didSwap = true ;
}
} while (didSwap) ;
}
addressBook &addressBook::operator +=(const PERSON &p)
{
addPerson(p);
return *this;
};
addressBook addressBook::operator [](int x)
{
return people[x];
};
ostream &operator << (ostream &output, addressBook &ab)
{
PERSON tmp;
ab.getPerson(tmp);
output << tmp.fName << " " << tmp.lName << " " << tmp.Address << endl;
return output;
}
addressBook * addressBook::tempNew = NULL;
addressBook *addressBook::newbookInst()
{
if(tempNew == NULL)
{
tempNew = new addressBook;
}
return tempNew;
}
PERSON * addressBook::temPerson = NULL;
PERSON *addressBook::p()
{
if(temPerson == NULL)
{
temPerson = new PERSON;
}
return temPerson;
}
bool status;
char lName[50];
char fName[50];
void addressBook::writeRecord()
{
PEOPLE2 temp;
ofstream outFile("vectortest.dat", ios::app);
if(!outFile)
{
cout << "Error opening file for writing " << endl;
return;
}
for (vector<PERSON>::iterator iter = people.begin(), end = people.end(); iter != end; ++iter)
{
strncpy(temp.fName2, iter->fName.c_str(), 25);
strncpy(temp.lName2, iter->lName.c_str(), 25);
strncpy(temp.Address2, iter->Address.c_str(), 25);
outFile.write(reinterpret_cast<const char *>(&temp), sizeof(PEOPLE2));
}
outFile.close();
}
void addressBook::showRecord(int pickNum)
{
PEOPLE2 p;
ifstream indata("vectortest.dat", ios::binary);
if(!indata)
{
cout << "Error opening file for reading " << endl;
exit(0);
}
indata.seekg(pickNum * sizeof(PEOPLE2));
indata.read(reinterpret_cast<char *>(&p), sizeof(PEOPLE2));
cout << p.fName2 << " " << p.lName2 << " " << p.Address2 << " " << endl;
indata.close();
}
void addressBook::showAll()
{
ifstream indata("vectortest.dat", ios::binary);
for(int i = 0; i < indata.end; i ++)
{
showRecord(i);
}
}
}
你是什麼意思,「它只打印出硬編碼到我的PERSON結構從以前的任務」? AND,什麼是'indata.end'?這不是記錄的數量,是嗎? – Arun 2013-04-06 23:49:02
我會在主帖子中彈出該代碼,以顯示它在做什麼 – 2013-04-06 23:53:16
另外,您會發布「PEOPLE2」的聲明嗎? – Arun 2013-04-06 23:54:44