Question

例如，我有這個字符串"this is a testing string"，我想測試天氣詞「串」在那裏。 我將如何在PHP中做到這一點？

$theMessage = addslashes(strip_tags($_POST['message'])); 

$s1='binuang'; 
$s2='ilad'; 
$s3='fraud'; 
$s4='fake'; 
$s5='ayaw mo ug tuo'; 
$s6='pangilad'; 
$s7='bot2'; 
$s8='bot-bot'; 
$s9='botbot'; 
$s10='di tinuod'; 
$s11='di ni tinuod'; 

$t1=strpos($theMessage, $s1); 
$t2=strpos($theMessage, $s2); 
$t3=strpos($theMessage, $s3); 
$t4=strpos($theMessage, $s4); 
$t5=strpos($theMessage, $s5); 
$t6=strpos($theMessage, $s6); 
$t7=strpos($theMessage, $s7); 
$t8=strpos($theMessage, $s8); 
$t9=strpos($theMessage, $s9); 
$t10=strpos($theMessage, $s10); 
$t11=strpos($theMessage, $s11); 

if($t1===true || $t2===true || $t3===true || $t4===true || $t5===true || $t6===true || $t7===true || $t8===true || $t9===true || $t10===true || $t11===true) 
{ 

$sql2=mysql_query("UPDATE property SET valid='1' where p_id='$q'"); 

} 

Answer 1

使用strpos：http://php.net/manual/en/function.strpos.php

Answer 2

您可以使用preg_match();或 ...

會更容易些，因爲它不會涉及到正則表達式，但呵呵，實驗，看看有什麼適合你最好！

好了，讓我們開始...
1）您將通過把所有這些「壞」字陣列內，像賺了不少：

$badwords = array('badword1', 'badword2', 'badwords3'); // and so on... 

2）讓我們通過所有的BADWORDS運行，檢查他們的消息中的位置，有一個循環：

$found = 0; // just a simple counter, to populate if a bad word is found.. 
foreach($badwords as $word){ // for each "bad word" from array, used in loop as "$word" 
    if(strpos($theMessage, $word) !== 'false'){ // if we've found the word... 
     $found++; // ...plus one for found 
    } 
} 

3）查詢部分......我們是否已發現不好的話，如果是，我們顯示錯誤，否則與查詢繼續：

if($found > 0){ // self explanatory... 
    echo 'Error, bad words found, you shall not pass!'; 
}else{ 
    $query = mysql_query("UPDATE `property` SET `valid` = '1' WHERE `p_id` = '{$q}';"); // {$q} == $q, just formatting preference. 
} 

4）總之，只是爲了好玩和回答的長度：

$theMessage = addslashes(strip_tags($_POST['message'])); 
$badwords = array('badword1', 'badword2', 'badwords3'); // and so on... 

$found = 0; // just a simple counter, to populate if a bad word is found.. 
foreach($badwords as $word){ // for each "bad word" from array, used in loop as "$word" 
    if(strpos($theMessage, $word) !== 'false'){ // if we've found the word... 
     $found++; // ...plus one for found 
    } 
} 

if($found > 0){ // self explanatory... 
    echo 'Error, bad words found, you shall not pass!'; 
}else{ 
    $query = mysql_query("UPDATE `property` SET `valid` = '1' WHERE `p_id` = '{$q}';"); // {$q} == $q, just formatting preference. 
} 

玩得開心！

P.S.我不知道這是否有效，目前無法測試，但我認爲應該。

http://php.net/manual/en/function.preg-match.php
http://php.net/manual/en/function.strpos.php

Answer 3

如果它是一個直接匹配，你可以這樣做：

$stringToTest="this is a testing string"; 
$findMe="string"; 


if(strpos($stringToTest,$findMe)!==FALSE){ 
//something 
} 

然而，因爲在字符串中的位置可以是零的情況下，你需要做的！== FALSE方法精確解決所有病例

Answer 4

$haystack = "this is a testing string."; 
$needle = "string"; 
$found = strstr($haystack, $needle); 

if($found!==FALSE) 
    echo "I found it!";