4
的利用多重模塊我有點新的Python的。我一直在學習和研究多處理模塊，並在使用鎖定時遇到了這個問題。無法跨鎖的過程之間，而在Python
下面是測試代碼：
import multiprocessing
from multiprocessing import Pool
class Param_Class():
#Initialisation.
def __init__(self):
self.counter = multiprocessing.Value('i',0)
self.lock = multiprocessing.Lock()
def inc_counter(self):
lk.acquire()
print('Locked {}'.format(multiprocessing.current_process().name))
self.counter.value+=1
lk.release()
print('Released {}'.format(multiprocessing.current_process().name))
param_class = Param_Class()
def init(lock):
global lk
lk = lock
def target():
param_class.inc_counter()
code = 0
return code
def handler(i):
if i<50:
code = target()
print(param_class.counter.value)
if __name__ == '__main__':
p = Pool(processes=2,initializer=init, initargs=(param_class.lock,))
p.map_async(handler,range(50))
p.close()
p.join()
我的預期是什麼，而另一種是執行，所以我的計數器應增加每次執行要麼進程的時間被鎖每個進程。然而，的互鎖過程和第二處理之間發生的事情是工作在櫃檯上的副本。
這裏是輸出：
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
1
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
2
Released SpawnPoolWorker-2
1
Locked SpawnPoolWorker-1
Locked SpawnPoolWorker-2
Released SpawnPoolWorker-1
Released SpawnPoolWorker-2
3
2
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
4
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
3
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
5
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
4
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
6
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
5
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
7
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
6
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
8
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
7
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
9
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
8
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
10
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
9
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
11
Released SpawnPoolWorker-2
10
Locked SpawnPoolWorker-1
Locked SpawnPoolWorker-2
Released SpawnPoolWorker-1
Released SpawnPoolWorker-2
12
11
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
13
Released SpawnPoolWorker-2
12
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
14
Released SpawnPoolWorker-2
13
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
15
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
14
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
16
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
15
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
17
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
16
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
18
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
17
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
19
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
18
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
20
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
19
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
21
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
20
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
22
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
21
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
23
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
22
Released SpawnPoolWorker-1
24
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
25
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
26
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
27
Locked SpawnPoolWorker-1
Released SpawnPoolWorker-1
28
所需的輸出應該是這樣的：
Locked SpawnPoolWorker-1
1
Released SpawnPoolWorker-1
Locked SpawnPoolWorker-2
2
Released SpawnPoolWorker-2
Locked SpawnPoolWorker-1
3
Released SpawnPoolWorker-1
.
.
.
.
.
.
.
Locked SpawnPoolWorker-2
50
Released SpawnPoolWorker-2
我已經提到this瞭解初始化鎖和繼承它。我無法理解我弄亂了什麼。是鎖定還是調用或使用類實例或者目標函數本身。請用一些理論來詳細說明它以支持它。我想了解這一點，而不僅僅是解決它。
注意如何，得到的輸出，它的工作原理是從值24有望28和處理2剛剛停止工作。需要澄清那一個。
P.S .:我想避免使用管理器，因爲它是重量級，如鏈接答案中所述。另外，我不想消除執行的部分併發性，因爲我將使用它不需要被鎖定其他變量，我想模塊保持快速和Python的。