2009-08-03 73 views
11

distance_of_time_in_words是偉大的,但有時它不夠精細。更精確distance_of_time_in_words

我需要一個函數來報告單詞中的確切時間距離。例如,上午7:50到10:10應該是「2小時20分鐘」的距離,而不是「大約2小時」或任何distance_of_time_in_words會做的。

我的使用案例是報告火車時刻表,特別是一個特定的火車車程需要多長時間。

+0

更新鏈接:https://github.com/radar/dotiw其實更好, – 2009-08-13 14:44:16

回答

2
def distance_of_time_in_hours_and_minutes(from_time, to_time) 
    from_time = from_time.to_time if from_time.respond_to?(:to_time) 
    to_time = to_time.to_time if to_time.respond_to?(:to_time) 
    distance_in_hours = (((to_time - from_time).abs)/3600).round 
    distance_in_minutes = ((((to_time - from_time).abs) % 3600)/60).round 

    difference_in_words = '' 

    difference_in_words << "#{distance_in_hours} #{distance_in_hours > 1 ? 'hours' : 'hour' } and " if distance_in_hours > 0 
    difference_in_words << "#{distance_in_minutes} #{distance_in_minutes == 1 ? 'minute' : 'minutes' }" 
end 
+1

我會改行 個distance_in_hours =(((TO_TIME - FROM_TIME)。ABS)/ 3600).round 到 distance_in_hours =(((TO_TIME - FROM_TIME)。ABS)/ 3600).to_i 的輪將上舍入,使1.5小時看起來像2小時30分鐘 – theschmitzer 2010-08-06 20:35:02

2

上面的代碼混淆了我的Rubymine ......並且我不確定它實際上是否正確。我重建它,如下所示:


def distance_of_time_in_hours_and_minutes(from_time, to_time) 
    from_time = from_time.to_time if from_time.respond_to?(:to_time) 
    to_time = to_time.to_time if to_time.respond_to?(:to_time) 
    dist = to_time - from_time 
    minutes = (dist.abs/60).round 
    hours = minutes/60 
    minutes = minutes - (hours * 60) 

    words = dist <= 0 ? '' : '-' 

    words << "#{hours} #{hours > 1 ? 'hours' : 'hour' } and " if hours > 0 
    words << "#{minutes} #{minutes == 1 ? 'minute' : 'minutes' }" 
end 

下面是一些Rspec的針對上述:


describe "Distance of Time in Hours and Minutes" do 
    before do 
    @time1 = Time.utc(2010,"sep",7,14,15,3) 
    @time2 = @time1 + 28 
    @time3 = @time1 + 30 
    @time4 = @time1 + 60 
    @time5 = @time1 + 60*60 
    @time6 = @time1 + 60*60 + 60 
    @time7 = @time1 + 60*60 + 5*60 
    end 

    it "calculates time differences properly" do 
    distance_of_time_in_hours_and_minutes(@time1, @time1).should == "0 minutes" 
    distance_of_time_in_hours_and_minutes(@time1, @time2).should == "0 minutes" 
    distance_of_time_in_hours_and_minutes(@time1, @time3).should == "1 minute" 
    distance_of_time_in_hours_and_minutes(@time1, @time4).should == "1 minute" 
    distance_of_time_in_hours_and_minutes(@time1, @time5).should == "1 hour and 0 minutes" 
    distance_of_time_in_hours_and_minutes(@time1, @time6).should == "1 hour and 1 minute" 
    distance_of_time_in_hours_and_minutes(@time1, @time7).should == "1 hour and 5 minutes" 
    distance_of_time_in_hours_and_minutes(@time7, @time1).should == "-1 hour and 5 minutes" 
    distance_of_time_in_hours_and_minutes(@time3, @time1).should == "-1 minute" 
    end 
end 

(請注意,我在我的編碼環境,以避免NoMethodError誤差過的distance_of_time_in_miles前插每次調用與helper -

+0

是不是這一行「words = dist <= 0? '':' - '「是錯誤的方法?如果dist是正數,則返回負號,而如果dist是負數,則可能會返回它。 – 2011-01-18 13:16:33