谷歌腳本來複制和重複行

Question

大家好我不擅長腳本，只需要一些幫助，我想要做的是複製和重複單元格a，b，c，d，e，基於信息在單元格F和G.

在單元格d和e是日期和他們需要增加單元格中的值，並繼續重複基於G中的值，我做了一個示例工作表，在工作表輸入是數據，並在表格輸出它顯示我需要的結果。但是所有信息都需要保留在輸入表單上，而不是其他表單。希望你能理解我看到樣本表的含義。在單元格f的表格中，它表示幾周後，這會在幾周後變好。

Title Description  Location  Start Time  End Time  repeate every how many times to repeat                    
test tester   here   9/7/17 20:00 9/7/17 20:10 2 weeks  4                   
fake data   home   15/7/17 15:00 15/7/17 16:00 4 weeks  3 

original Google sheet

我想獲得的總體目標是當一個表單提交能夠重複事件自動添加到谷歌日曆腳本，但如果我可以重複我需要在數據然後我可以設置基於天的重現事件，因爲我相信日曆的重複事件只讓你每天每週做一次..

或者任何人都可以指向我網站，我可能會找到一些信息來幫助我嗎？

Answer 1

我把重複改爲幾天而不是幾周。

function repeatingEvents() 
{ 
    var ss=SpreadsheetApp.getActiveSpreadsheet(); 
    var sht=ss.getSheetByName('Repeat'); 
    var rng=sht.getDataRange();//Get all of the data on the sheet 
    var rngA=rng.getValues(); 
    var day=86400000;//milliseconds in a day 
    var week=604800000;//millisecond in a week 
    for(var i=0;i<rngA.length;i++) 
    { 
     if(rngA[i][6]>0)//If the number of repeats is greater than zero 
     { 
     var cnt=Number(rngA[i][6]);//cnt is number of repeats 
     for(var n=0;n<cnt;n++) 
     { 
      var row=[]; 
      row.push(rngA[i][0]);//column A 
      row.push(rngA[i][1]);//column B 
      row.push(rngA[i][2]);//column C 
      row.push(new Date(rngA[i][3].getTime() + (rngA[i][5] * (n + 1) * day)));//old date time plus repeat duration * repeat count * milliseconds in a day in column D 
      row.push(new Date(rngA[i][4].getTime() + (rngA[i][5] * (n + 1) * day)));//column E 
      row.push(rngA[i][5]);//Column F 
      row.push('');//column G get zeroed out so script won't come back and do it again without human interaction 
      sht.appendRow(row);//add new event 
     } 
     sht.getRange(i+1,7).setValue(0);//zero out initial number of repeats because I use this to determine when repeats are required 
     } 
    } 
    sht.getRange(2,1,sht.getLastRow(),sht.getLastColumn()).sort({column:4,ascending:true});//Sort Spreadsheet by starting date 
} 

這是我的電子表格的樣子。

好吧，我改變了代碼以適應您最近添加的ID的變化。它已經在您的電子表格中，我在這裏重複。爲參考目的。

function repeatingEvents() 
{ 
    var ss=SpreadsheetApp.getActiveSpreadsheet(); 
    var sht=ss.getSheetByName('input'); 
    var rng=sht.getDataRange();//Get all of the data on the sheet 
    var rngA=rng.getValues(); 
    var day=86400000;//milliseconds in a day 
    var week=604800000;//millisecond in a week 
    for(var i=0;i<rngA.length;i++) 
    { 
     if(rngA[i][7]>0)//If the number of repeats is greater than zero 
     { 
     var cnt=Number(rngA[i][7]);//cnt is number of repeats 
     for(var n=0;n<cnt;n++) 
     { 
      var row=[]; 
      row.push(rngA[i][0]);//A 
      row.push(rngA[i][1]);//B 
      row.push(rngA[i][2]);//C 
      row.push(new Date(rngA[i][3].getTime() + (rngA[i][6] * (n + 1) * day)));//old date time plus repeat duration * repeat count * milliseconds in a day D 
      row.push(new Date(rngA[i][4].getTime() + (rngA[i][6] * (n + 1) * day)));//E 
      row.push(rngA[i][5]);//F 
      row.push(rngA[i][6]);//G 
      row.push('');//H 
      sht.appendRow(row);//add new event 
     } 
     sht.getRange(i+1,8).setValue(0);//zero out initial number of repeats because I use this to determine when repeats are required 
     } 
    } 
    sht.getRange(2,1,sht.getLastRow(),sht.getLastColumn()).sort({column:4,ascending:true});//Sort Spreadsheet by starting date 
} 

Answer 2

我已經改變了列F和G到G和H，我嘗試過編輯腳本這項工作，一切似乎離時，增加了在相隔幾天的工作重複它仍然增加了他們在F和不是G不能解決爲什麼？

function repeatingEvents() 
 
{ 
 
    var ss=SpreadsheetApp.getActiveSpreadsheet(); 
 
    var sht=ss.getSheetByName('Calendar'); 
 
    var rng=sht.getDataRange();//Get all of the data on the sheet 
 
    var rngA=rng.getValues(); 
 
    var day=86400000;//milliseconds in a day 
 
    var week=604800000;//millisecond in a week 
 
    for(var i=0;i<rngA.length;i++) 
 
    { 
 
     if(rngA[i][7]>0)//If the number of repeats is greater than zero 
 
     { 
 
     var cnt=Number(rngA[i][7]);//cnt is number of repeats 
 
     for(var n=0;n<cnt;n++) 
 
     { 
 
      var row=[]; 
 
      row.push(rngA[i][0]);//A 
 
      row.push(rngA[i][1]);//B 
 
      row.push(rngA[i][2]);//C 
 
      row.push(new Date(rngA[i][3].getTime() + (rngA[i][6] * (n + 1) * day)));//old date time plus repeat duration * repeat count * milliseconds in a day D 
 
      row.push(new Date(rngA[i][4].getTime() + (rngA[i][6] * (n + 1) * day)));//E 
 
      row.push(rngA[i][5]);//E This needs to be here other wise 6 and 7 become 5 & 6 
 
      row.push(rngA[i][6]);//F 
 
      row.push(rngA[i][7]);//G 
 
      sht.appendRow(row);//add new event 
 
     } 
 
     sht.getRange(i+1,8).setValue(0);//zero out initial number of repeats because I use this to determine when repeats are required 
 
     } 
 
    } 
 
    sht.getRange(2,1,sht.getLastRow(),sht.getLastColumn()).sort({column:4,ascending:true});//Sort Spreadsheet by starting date 
 
}