我特林通過Ajax表單數據發送到節點JS,
我使用快遞與身體解析器節點JS
但我正在逐漸未定義的REQ。身體阿賈克斯後的數據發送給快遞JS身體解析器
我搜索了每一個網絡,並嘗試了很多東西,沒有爲我工作 請幫助我正確的方式做到這一點。
| * | HTML代碼:
<html lang="en">
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<title>Add</title>
</head>
<body>
<h1>Welcome to Website </h1>
<form id="addUserForm">
<h3> Enter the your details : </h3>
Name :<br><input type="text" name="nameView"><br><br>
Email :<br><input type="email" name="mailView"><br><br>
Mobile :<br><input type="number" name="mobileView"><br><br>
<input type="submit" value="Submit">
</form>
| * | Ajax代碼:
<script>
$(document).ready(function()
{
$('#addUserForm').submit(function()
{
var formDataVar = new FormData($(this)[0]);
console.log(formDataVar);
$.ajax({
url: '/addUserFormSubmit',
type:'POST',
data: formDataVar,
dataType: 'json',
contentType: false,
processData: false,
}).done(function(ResJryVar)
{
console.log(ResJryVar);
});
})
});
</script>
</body>
</html>
| * |我也試過:
var formDataVar = new FormData();
formDataVar.append('nameView', input.files[0]);
formDataVar.append('mailView', input.files[1]);
formDataVar.append('mobileView', input.files[2]);
和
var formDataVar = {};
$.each($('#addUserForm').serializeArray(), function(i, field)
{
formDataVar[field.name] = field.value;
});
| * |節點JS代碼:
var express = require("express");
var bodyParser = require("body-parser");
var app = express();
app.listen(8888,function()
{
console.log("Server Started and Running ...");
});
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({extended: true}));
app.get('/',addUserFormFnc);
app.post('/addUserFormSubmit',addUserSubmitFnc);
function addUserFormFnc(req, res)
{
res.sendFile('addUser.html', {root: __dirname });
}
function addUserSubmitFnc(req, res)
{
console.log("Data Received : ");
var userObjVar =
{
nameView: req.body.nameView,
mailView: req.body.mailView,
mobileView: req.body.mobileView
};
console.log(userObjVar);
res.send(userObjVar);
}
如果你有url編碼數據,它應該在req.body上可用,而不是req.data。對於多部分/表單數據,請查看Muller中間件包。 – djfdev
抱歉編輯我的問題。它的要求。我只是使用表單。 action ='/ addUserFormSubmit'的作品。但是當我從阿賈克斯發送,它不會工作 –