我正在嘗試編寫一些使用管道在父進程和它的子進程之間進行通信的代碼。但是,我的管道在我第一次使用後似乎放棄了(也就是說,在第一次使用管道後停止工作)。我不確定如何解決這個問題,任何幫助將不勝感激。我也知道,我在這裏使用的一些編碼練習並不是很理想(主要是使用睡眠)。在C問題中的管道通信
const int READ = 0;
const int WRITE = 1;
char* COOP = "Criminal cooperates\n";
char* SIL = "Criminal doesn't talk\n";
char* reader(int);
void writer(int, char *c);
int main()
{
int c1pipe1[2];
int c1pipe2[2];
int c2pipe1[2];
int c2pipe2[2];
int c1sentence = 0;
int c2sentence = 0;
int r;
int c;
pipe(c1pipe1);
pipe(c1pipe2);
pipe(c2pipe1);
pipe(c2pipe2);
int C2;
int C1 = fork();
if(C1 > 0)
C2 = fork();
if(C1 < 0 || C2 < 0) //error
{
perror("fork() failed");
exit(1);
}
else if(C1 == 0)
{
close(c1pipe1[WRITE]);
close(c1pipe2[READ]);
for(c = 0; c < 10; c++)
{
r = rand();
//printf("C1 rand = %d\n", r%2);
if(r % 2 == 1)
writer(c1pipe2[WRITE], "1");
else
writer(c1pipe2[WRITE], "0");
sleep(1);
}
exit(0);
}
else if(C2 == 0)
{
close(c2pipe1[WRITE]);
close(c2pipe2[READ]);
for(c = 0; c < 10; c++)
{
r = rand();
//printf("C2 rand = %d\n", r%2);
if(r % 2 == 1)
writer(c2pipe2[WRITE], "1");
else
writer(c2pipe2[WRITE], "0");
sleep(1);
}
exit(0);
}
else //parent
{
int buff1; //stores choice of c1
int buff2; //stores choice of c2
close(c1pipe1[READ]);
close(c1pipe2[WRITE]);
close(c2pipe1[READ]);
close(c2pipe2[WRITE]);
for(c = 0; c< 10; c++)
{
buff1 = atoi(reader(c1pipe2[READ]));
buff2 = atoi(reader(c2pipe2[READ]));
printf("C1's \(%d)\ choice trial %d : %d\n", C1, c+1, buff1);
printf("C2's \(%d)\ choice trial %d : %d\n", C2, c+1, buff2);
if(buff1 && buff2) //c1 and c2 cooperate with police
{
c1sentence = c1sentence + 6;
c2sentence = c2sentence + 6;
}
else if(buff1 || buff2) // one cooperates, one is silent
{
if(buff1) // if c1 cooperates and c2 is silent
{
c1sentence = c1sentence + 0;
c2sentence = c2sentence + 10;
}
else // if c2 cooperates and c1 is silent
{
c1sentence = c1sentence + 10;
c2sentence = c2sentence + 0;
}
}
else if(!(buff1 && buff2)) //both c1 and c2 are silent
{
c1sentence = c1sentence + 1;
c2sentence = c2sentence + 1;
}
sleep(1);
}
printf("C1 is in jail for %d years total\n", c1sentence);
printf("C2 is in jail for %d years total\n", c2sentence);
exit(0);
}
exit(0);
}
void writer(int pipe_write_fd, char *c)
{
open(pipe_write_fd);
char* choice = c;
// Write to the pipe
write(pipe_write_fd, choice, strlen(choice));
// Close the pipe
// (Sends 'end of file' to reader)
close(pipe_write_fd);
}
char* reader(int pipe_read_fd)
{
open(pipe_read_fd);
// Allocate buffer to store
// result of read
int buffer_size = 1024;
char buffer[buffer_size];
// Keep reading until we exhaust
// buffer or reach end of file
int i = 0;
while (i < buffer_size
&& read(pipe_read_fd, &buffer[i], 1) > 0)
{ i++; }
if (i < buffer_size) {
// Add null termination
buffer[i] = '\0';
} else {
// We exhausted buffer
fprintf(stderr, "Warning: buffer full.\n");
buffer[buffer_size-1] = '\0';
}
//printf("%s", buffer);
// Close the pipe
close(pipe_read_fd);
return buffer;
}
哈哈,這似乎是經典的「opertive系統」練習考試:D不是嗎? – dynamic 2011-02-12 23:38:50
更多的作業,我不明白哈哈。我不會問,除了我花了很多時間在網上搜索答案/其他人,並且無法得到答案。 – Mike 2011-02-13 00:01:03
添加作業標籤:) – 2011-04-16 15:35:55