如何顯示沒有在PHP

獨特價值（ID）模態的具體數據我有一個從API未來的數據集。數據中沒有id屬性。當我們要顯示其ID形式的基礎上，具體的數據，我們在html聲明data-id屬性，但如果我們沒有相關數據的任何id。我們如何在模態中顯示它的內容？如何顯示沒有在PHP

查看我的數據，我正在顯示name並有more-info按鈕用於modal。我應該怎麼做，當有人點擊more-info按鈕。它顯示具體內容？

還有一個在我怎麼能分頁它在PHP中的數據下一個網址？

{ 
"count": 37, 
"next": "http://some-url/api/stars/?page=2", 
"previous": null, 
"results": [ 
    { 
     "name": "Sentinel-class landing craft", 
     "model": "Sentinel-class landing craft", 
     "manufacturer": "Sienar Fleet Systems, Cyngus Spaceworks", 
     "cost_in_credits": "240000", 
     "length": "38", 
     "max_atmosphering_speed": "1000", 
     "crew": "5", 
     "passengers": "75", 
     "cargo_capacity": "180000", 
     "consumables": "1 month", 
     "hyperdrive_rating": "1.0", 
     "MGLT": "70", 
     "starship_class": "landing craft", 
     "pilots": [], 
     "films": [ 
      "http://some-url/api/films/1/" 
     ], 
     "created": "2014-12-10T15:48:00.586000Z", 
     "edited": "2014-12-22T17:35:44.431407Z", 
     "url": "http://some-url/api/stars/5/" 
    }, 
    { 
     "name": "Death Star", 
     "model": "DS-1 Orbital Battle Station", 
     "manufacturer": "Imperial Department of Military Research, Sienar Fleet Systems", 
     "cost_in_credits": "1000000000000", 
     "length": "120000", 
     "max_atmosphering_speed": "n/a", 
     "crew": "342953", 
     "passengers": "843342", 
     "cargo_capacity": "1000000000000", 
     "consumables": "3 years", 
     "hyperdrive_rating": "4.0", 
     "MGLT": "10", 
     "starship_class": "Deep Space Mobile Battlestation", 
     "pilots": [], 
     "films": [ 
      "http://some-url.co/api/films/1/" 
     ], 
     "created": "2014-12-10T16:36:50.509000Z", 
     "edited": "2014-12-22T17:35:44.452589Z", 
     "url": "http://some-url.co/api/starships/9/" 
    },

來源

2016-12-15 Qasim Ali

你是怎麼得到這個數據？依據是什麼？，你怎麼指標數據進行查詢？ – madalinivascu

實際上，我從'API'數據中獲取這些數據的形式是'JSON' –

您的db似乎有一個唯一的關鍵字，與我在urls中看到的特定值關聯，爲什麼不從服務提供商呢？ – madalinivascu

$arrayData = json_decode($jsonData); 
$i=0; 
foreach($arrayData->results as $data) 
{ 
    $arrayData->results[$i]->name; 
    $arrayData->results[$i]->id=$i; 
    $i++; 
}

來源

2016-12-15 12:52:21 Parthu

如何顯示沒有在PHP

回答

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