2
早上好失敗後，傳遞字符串到Twitter符號
我試圖傳遞一個字符串到Twitter，使用下面的代碼
// The message you want to send
$message = "http://www.smartphonesoft.com/index.php?option=com_mtree&task=viewlink&link_id=" .$link_id . " " ."Android Software" . " " .$link_name . " " . $metadesc;
// The twitter API address
$url = 'http://twitter.com/statuses/update.xml';
// Alternative JSON version
// $url = 'http://twitter.com/statuses/update.json';
// Set up and execute the curl process
$curl_handle = curl_init();
curl_setopt($curl_handle, CURLOPT_URL, "$url");
curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl_handle, CURLOPT_POST, 1);
curl_setopt($curl_handle, CURLOPT_POSTFIELDS, "status=$message");
curl_setopt($curl_handle, CURLOPT_USERPWD, "$username:$password");
$buffer = curl_exec($curl_handle);
curl_close($curl_handle);
然而，關於Twitter的出現都是以
鏈接http://www.smartphonesoft.com/index.php?option=com_mtree
因爲在這裏可以看到http://twitter.com/smartphonesft
如何在「＆」之後通過所有內容？