查詢無效：列數並不在行匹配值計數1

Question

我有一個奇怪的問題，我通過PHP發送SQL查詢：

INSERT INTO `lib_plex` (`id`, `active`, `lastUpdated`, `entry_date`, `entry_ip`, `address`, `city`, `state_iso`, `zip_code`, `plex_type`, `price`, `has_garage`, `has_indoor_parking`, `has_outdoor_parking`, `has_pool`, `has_fireplace`, `average_nb_room`, `construction_year`, `building_material`) 

VALUES ('','1','2010-10-27 13:22:59','2010-10-27 13:22:59','2130706433','COMMERCE ST.','85825','OK','73521','commercial','595000','0','0','0','0','0','11','','Aluminum Siding') 

它拋出我這個錯誤： 無效查詢：列計數與第1行的值計數不匹配。 雖然，當我粘貼並運行相同的確切查詢在PhpMyAdmin，它完美的作品，所以它讓我很困惑...

我統計的列數和值的數量，他們匹配（19 ）。我試圖刪除'id'字段，因爲它是自動遞增的，但它沒有改變任何東西。我究竟做錯了什麼？爲什麼它在PhpMyAdmin中工作？

感謝您的幫助！

編輯：

這裏的PHP代碼：

$values = array('', 1, $lastUpdated, $entry_date, $entry_ip, $streetName, $cityId, $listing['stateorprovince'], $listing['postalcode'], $listing['type'], $listing['listprice'], $has_garage, $has_indoor_parking, $has_outdoor_parking, $has_pool, $has_fireplace, $average_nb_room, $listing['yearbuilt'], $listing['exteriortype']); 

$q = "INSERT INTO `lib_plex` (`id`, `active`, `lastUpdated`, `entry_date`, `entry_ip`, `address`, `city`, `state_iso`, `zip_code`, `plex_type`, `price`, `has_garage`, `has_indoor_parking`, `has_outdoor_parking`, `has_pool`, `has_fireplace`, `average_nb_room`, `construction_year`, `building_material`) 
VALUES ('".htmlentities(implode("','",$values),ENT_QUOTES)."')"; 

$this->execMysqlQuery($q); 

和被調用的方法：

private function execMysqlQuery($q, $returnResults = false, $returnInsertId = false){ 
$c = mysql_connect(DB_SERVER,DB_LOGIN,DB_PASSWORD); 
mysql_select_db(DB_NAME, $c); 

$result = mysql_query($q); 
if (!$result) { 
    die('Invalid query: ' . mysql_error(). "<br/>=>".$q); 
} 

if ($returnInsertId) 
    return mysql_insert_id(); 

mysql_close($c); 

if ($returnResults) 
    return $result; 

return true; 
} 

和錯誤：

Invalid query: Column count doesn't match value count at row 1 
=>INSERT INTO `lib_plex` (`id`, `active`, `lastUpdated`, `entry_date`, `entry_ip`, `address`, `city`, `state_iso`, `zip_code`, `plex_type`, `price`, `has_garage`, `has_indoor_parking`, `has_outdoor_parking`, `has_pool`, `has_fireplace`, `average_nb_room`, `construction_year`, `building_material`) VALUES ('','1','2010-10-27 13:47:35','2010-10-27 13:47:35','2130706433','COMMERCE ST.','85825','OK','73521','commercial','595000','0','0','0','0','0','11','','Aluminum Siding') 

Answer 1

如果您打印$q，我敢打賭它看起來像這樣：

INSERT INTO `lib_plex` (`id`, `active`, `lastUpdated`, `entry_date`, `entry_ip`, `address`, `city`, `state_iso`, `zip_code`, `plex_type`, `price`, `has_garage`, `has_indoor_parking`, `has_outdoor_parking`, `has_pool`, `has_fireplace`, `average_nb_room`, `construction_year`, `building_material`) 
VALUES ('','1','2010-10-27 13:22:59','2010-10-27 13:22:59','2130706433','COMMERCE ST.','85825','OK','73521','commercial','595000','0','0','0','0','0','11','','Aluminum Siding'); 

（我沒有PHP工作;這是一個猜測）

換句話說，htmlentities正在把你的報價變成HTML實體。具體而言，請將'轉換爲'

請勿在沒有發送到Web瀏覽器的情況下使用htmlentities。對每個單獨的值用你的數據庫驅動程序的方法逃避（mysql_real_escape_string）在被送到

編輯：更重要的是，使用預準備語句和數據MySQLi或PDO結合，它會自動逃跑的數據，你將它綁定。

Answer 2

if ($insert) { 
    $query = "INSERT INTO employee VALUES ($empno,'$lname','$fname','$init','$gender','$bdate','$dept','$position',$pay,$dayswork,$otrate,$othrs,$allow,$advances,$insurance,'')"; 
    $msg = "New record saved!"; 
    } 
    else { 
    $query = "UPDATE employee SET empno=$empno,lname='$lname',fname='$fname',init= '$init',gender='$gender',bdate='$bdate',dept='$dept',position='$position',pay=$pay,dayswork=$dayswork,otrate=$otrate,othrs=$othrs,allow=$allow,advances=$advances,insurance=$insurance WHERE empno = $empno"; 
    $msg = "Record updated!"; 
    } 
    include 'include/dbconnection.php'; 
    $result=mysql_query ($query,$link) or die ("invalid query".mysql_error());