在選擇器NSTimer錯誤

Question

我想使用NSTimer從另一個訪問方法時，延遲。我的意思是，我希望movebricksdown的方法可以在幾秒鐘後被訪問，而不是立刻從我的findmatches方法中找到。

但是，我在@selector部件上看到了一條錯誤消息。

我用

delaymovingbrickdowntimer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(movebricksdown: x Y: y Direction: Dir) userInfo:nil repeats:YES]; 

把延遲。

我知道它會工作，如果它說@ selector（movebricksdown），但我需要x，y和Dir值標記到movebricksdown方法。

我在做什麼錯了，當我使用

delaymovingbrickdowntimer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(movebricksdown: x Y: y Direction: Dir) userInfo:nil repeats:YES]; 

？

ps。 X，Y和導演都是整數提前

***UPDATE

感謝* ** * ** * ** * ** * ** * ** * ** * *** 我試了一下這樣的...

//the method movebricksdown 
-(void)movebricksdown: (int) x Y: (int) y Direction: (int) Dir 

//The method that is called from the NSTimer statement 
- (void) moveBricksDown:(NSTimer *) timer { 
    NSDictionary *dict = [timer userInfo]; //warning: local declaration of 'timer' hides instance variable 


    [self movebricksdown:[[dict objectForKey:@"x"] intValue] Y:[[dict objectForKey:@"y"] intValue] Direction:[dict objectForKey:@"Dir"]]; //warning: passing argument 3 of 'movebricksdown:Y:Direction:' makes integer from pointer without a cast 


} 

NSNumber *newX = [NSNumber numberWithInt:x]; 
NSNumber *newY = [NSNumber numberWithInt:y]; 
NSNumber *newDir = [NSNumber numberWithInt:Dir]; 

NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:newX, @"x", newY, @"y", newDir, @"dir", nil]; 
timer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(moveBricksDown:) userInfo:dict repeats:NO]; 

** * **UPDATE* ** * ** * * * * ** * *

我用performselector代替它解決了它。

感謝任何方式對所有的幫助:)

Answer 1

兩件事情：

a）您不能參數傳遞到由NSTimer調用的方法。

b）您的@selector語法不正確。

一個解決辦法是到的參數的NSDictionary通關到NSTimer的userInfo：

- (void) moveBricksDown:(NSTimer *) timer { 
    NSDictionary *dict = [timer userInfo]; 
    [self movebricksdown:[[dict objectForKey:@"x"] intValue] y:[[dict objectForKey:@"y"] intValue] Direction:[dict objectForKey:@"dir"]]; 
} 

#define NUMINT(x) [NSNumber numberWithInt:x] 

NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:NUMINT(x), @"x", NUMINT(y), @"y", Dir, @"dir", nil]; 
delaymovingbrickdowntimer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(moveBricksDown:) userInfo:args repeats:YES]; 

Answer 2

如果你想通過X，Y，迪爾在你的方法，然後把它作爲用戶信息..

NSMutableDictionary *dic=[NSMutableDictionary dictionaryWithObjectsAndKeys:x,@"x_value",y,@"y_value",dic,@"youdic",nil]; //Like this you can set your x,y and dic value and can get in movebricksdown method 
delaymovingbrickdowntimer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(movebricksdown) userInfo:dic repeats:YES]; 

Answer 3

通行證你在用戶信息對象參數（作爲字典或陣列）和fix the selector語法雅各布提及。它應該是這樣的。

@selector（方法名）//沒有參數

@selector（方法名:) //取 USERINFO對象

Apple Documentation on Selectors