嘗試將已建立的對象與另外兩個變量進行比較

Question

我已經將該對象稱爲client1（只是一個名稱）並且它包含（String description，int rating）的屬性其上的字符串是Dark Hair，並且該評級這是一個比賽制作程序。無論如何，我想比較方法getCompatability（）中的Client1（「黑髮」，7）; 所以用這種方法我想返回兩個匹配特徵的兼容性度量，或者如果描述不匹配，那麼只是一個零。所以這就是我想要做的

public return_type getCompatability（Characteristics otherRating） {把對象已經啓動的黑髮和7並將它們設置爲變量，以便我可以將它們與輸入的第二個進行比較。 }

一旦我把它們全都放在變量中，比較兩者將會很簡單。 還有另一種方法來比較兩個對象，也許getCompatability（對象，對象）比較兩個對象的變量。

Answer 1

我想你想要的是這樣的：

public class Characteristic { 
    private String description; 
    private int rating; 

    public Client(String description, int rating) { 
     this.description = description; 
     this.rating = rating; 
    } 

    public int getCompatability(Characteristic otherRating) { 
     if (description == null && otherRating.description != null || !description.equals(otherRating.description)) { 
      return 0; 
     } 

     int compatability; 
     // Perform comparison to calculate "compatability". 
     return compatability; 
    } 
} 

然後，它可以調用說：

Characteristic client1 = new Characteristic("Dark Hair", 7); 
Characteristic client2 = new Characteristic("Dark Hair", 4); 
Characteristic client3 = new Characteristic("Light Hair", 6); 
client1.getCompatability(client2); // Returns non-zero compatability since descriptions are the same 
client1.getCompatability(client3); // Returns zero compatability since descriptions are different 
client2.getCompatability(client3); // Returns zero compatability since descriptions are different 

Answer 2

可以使用

client1.getCompatiblity(client2); 



eg: 
class ClientDetails { 
    String description; 
    int rating; 
    //getter, setter 

    public int getCompatibility(Object client) { 
     //add null check & obj type check 
     ClientDetails client1 = (ClientDetails) client; 
     int count = 0; 
     if (description.equals(client1.getDescription()) { 
      count ++; 
     } 
     if (rating == client1.getRating()) { 
      count ++; 
     } 
     return count; 
    } 
}