我對XSLT非常陌生,這個示例看起來像是一種很好的學習方式,但是對我來說生活卻無法實現。我試圖並行標記化2個不同的字符串,並將它們組合成一個JSON數組。所以我想記號化measTypes [0]和匹配,以measResults [0],然後measTypes [1]和匹配measResults [1],等等如何在XSLT 2.0中應用並行模板定義
示例XML
<?xml version="1.0" encoding="UTF-8"?>
<measInfo measInfoId="1542455297">
<measTypes>1542455297 1542455298 1542455299 1542455300 1542455301 1542455302 1542455303 1542455304 1542455305 1542455306 1542455307 1542460296 1542460297 </measTypes>
<measValue measObjLdn="LTHAB0113422/ETHPORT:Cabinet No.=0, Subrack No.=1, Slot No.=7, Port No.=0, Subboard Type=BASE_BOARD">
<measResults>116967973 585560 496041572 682500 0 12583680 72080 520454 46670568 73432 2205837 1000000 1000000 </measResults>
</measValue>
<measValue measObjLdn="LTHAB0113422/ETHPORT:Cabinet No.=0, Subrack No.=1, Slot No.=7, Port No.=1, Subboard Type=BASE_BOARD">
<measResults>0 0 0 0 0 0 0 0 0 0 0 0 0 </measResults>
</measValue>
</measInfo>
XSLT 2.0,我至今
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform」 xmlns:xs="http://www.w3.org/2001/XMLSchema」 exclude-result-prefixes=「xs" version="2.0">
<xsl:output method="text" encoding="UTF-8" media-type="text/plain"/>
<xsl:strip-space elements="*"/>
<!--
<xsl:template match="/measInfo/measValue/measResults" name="measRes">
<xsl:for-each select=".">
{'measResult':{<xsl:value-of select="tokenize(normalize-space(.),'\s+')"/>}
</xsl:for-each>
</xsl:template>
-->
<xsl:template match="/" name="measObj">
[
<xsl:for-each select="measInfo/measValue">
'measObjLdn':'<xsl:value-of select="@measObjLdn"/>'
<xsl:call-template name="types"/>
</xsl:for-each>
]
<xsl:apply-templates />
</xsl:template>
<xsl:template match="/measInfo" name="types" >
'Metrics':[
<xsl:for-each select="tokenize(normalize-space(measTypes),'\s+')">
{'measType':'<xsl:value-of select="."/>'},<!-- <xsl:call-template name="measRes"/> -->
</xsl:for-each>
]
</xsl:template>
</xsl:stylesheet>
的JSON結果,我希望
[
'measObjLdn':"LTHAB0113422/ETHPORT:Cabinet No.=0, Subrack No.=1, Slot No.=7, Port No.=0, Subboard Type=BASE_BOARD",
'Metrics':[
{'measType':'1542455297','measResult':116967973},
{'measType':'1542455298','measResult':585560},
{'measType':'1542455299','measResult':496041572},
{'measType':'1542455300','measResult':682500},
{'measType':'1542455301','measResult':0},
{'measType':'1542455302','measResult':12583680},
{'measType':'1542455303','measResult':72080},
{'measType':'1542455304','measResult':520454},
{'measType':'1542455305','measResult':46670568},
{'measType':'1542455306','measResult':73432},
{'measType':'1542455307','measResult':2205837},
{'measType':'1542460296','measResult':1000000},
{'measType':'1542460297','measResult':1000000}
]
'measObjLdn':"LTHAB0113422/ETHPORT:Cabinet No.=0, Subrack No.=1, Slot No.=7, Port No.=1, Subboard Type=BASE_BOARD",
'Metrics':[
{'measType':'1542455297','measResult':0},
{'measType':'1542455298','measResult':0},
{'measType':'1542455299','measResult':0},
{'measType':'1542455300','measResult':0},
{'measType':'1542455301','measResult':0},
{'measType':'1542455302','measResult':0},
{'measType':'1542455303','measResult':0},
{'measType':'1542455304','measResult':0},
{'measType':'1542455305','measResult':0},
{'measType':'1542455306','measResult':0},
{'measType':'1542455307','measResult':0},
{'measType':'1542460296','measResult':0},
{'measType':'1542460297','measResult':0}
]
]
' 'measObjLdn':{LTHAB0113422/ETHPORT:內閣號= 0'並不像JSON來我。 –
對不起,太多的剪切和粘貼所有的代碼片段。現在應該是正確的 – Hans
您需要編寫一個模板或函數,以兩個序列作爲參數,然後爲每個序列中的第一個項目對創建JSON對象文本,並在序列的尾部分別調用模板函數。 XPath 3.0具有「for-each-pair」功能,但您當然可以在自己的函數中實現它。 https://www.w3.org/TR/xpath-functions-31/#func-for-each-pair –