如何查詢表，但忽略某些列，如ID =「1」和「2」

-3

我想查詢我的Mysql表返回某些行。我已經設置顯示錶中的每一行，但是我希望它不顯示ID = 1 ID = 2 ID = 3的行。如何查詢表，但忽略某些列，如ID =「1」和「2」

這是我的search.php，用於查詢數據庫。

<?php 
$responce = "Please enter a search term"; 
     if(!isset($_POST['searchterm'])) { 
     ?> 
     <br> 
     <br> 
     <h3 class="text-center" style="color:white"><u><?php echo $responce;?></u></h3><?php 
    } 


    $names = array(); 
    $link = array(); 


    if(isset($_POST['searchterm'])) { 
     mysql_connect("localhost", "root", "Password"); 
     mysql_select_db("videos"); 
     $search = mysql_real_escape_string(trim($_POST['searchterm'])); 


     $find_videos = mysql_query("SELECT * FROM `videos` WHERE `keywords` LIKE'%$search%'"); 
     while ($row = mysql_fetch_assoc($find_videos)) { 
      $names[] = $row['name']; 
      $link[] = $row['link']; 
     } 

    } 
    $deletethen = "DELETE FROM videos WHERE name = ''"; 

    include('session.php'); 
?> 
<!DOCTYPE html> 
<html> 
    <head> 
    <link href="http://vjs.zencdn.net/4.12/video-js.css" rel="stylesheet"> 
    <link rel="icon" type="image/ico" href="images/favicon.ico"> 
<script src="http://vjs.zencdn.net/4.12/video.js"></script> 
<link href="http://vjs.zencdn.net/4.12/video-js.css" rel="stylesheet"> 
<script src="http://vjs.zencdn.net/4.12/video.js"></script> 
<style type="text/css"> 
    .vjs-default-skin .vjs-control-bar { font-size: 125% } 
</style> 
    <meta charset="utf-8"> 
    <title>Network TV | search</title> 
    <meta name="viewport" content="width=device-width, initial-scale=1.0"> 
    <link rel="stylesheet" href="css/bootstrap.css" /> 
    <link href="css/font-awesome.css" rel="stylesheet" /> 
    <link href="css/3.1.1/animate.css" rel="stylesheet" /> 
    <link rel="stylesheet" href="css/styles.css" /> 
    </head> 
    <body style="background:center no-repeat fixed url('images/bg.jpg'); background-size: cover;overflow-x: hidden; background-color: black"> 
    <nav class="navbar navbar-default navbar-fixed-top"> 
     <div class="container"> 
     <div class="navbar-header"> 
      <button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#navbar" aria-expanded="false" aria-controls="navbar"> 
      <span class="sr-only">Toggle navigation</span> 
      <span class="icon-bar"></span> 
      <span class="icon-bar"></span> 
      <span class="icon-bar"></span> 
      </button> 
      <a class="navbar-brand" href="#">Network TV</a> 
     </div> 
     <div id="navbar" class="navbar-collapse collapse"> 
      <ul class="nav navbar-nav"> 
      <li class=""><a href="index.php">Home</a></li> 
      </ul> 
     </div><!--/.nav-collapse --> 
     </div> 
    </nav> 
     <section style="padding-top:100px; width:100%"class="container-fluid" id="section2"> 
        <h1 class="text-center" style="color:white">Network TV</h1> 
       <h3 class="text-center" style="color:white"><u>Search results</u></h3> 




             <table align="center" class="table" style="color: white; width:50%"> 
               <thead> 
               </thead> 
               <tbody> 
                <tr> 

                 <?php 
                 $i=0; 
                 foreach($names as $name) { 
                 echo '<tr> 
                   <td><h4>' . $name . '</h4></td> 
                   <td><a href="' .$link[$i]. '"><strong><h4><u>Watch now!</u></h4></strong></a></td></tr>'; 
                 $i++; 
                   } 
                   ?> 
                </tr> 
               </tbody> 
              </table> 
     </section> 
    <script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script> 
    <script src="//maxcdn.bootstrapcdn.com/bootstrap/3.3.4/js/bootstrap.min.js"></script> 

    <script src="js/scripts.js"></script> 
</html>

來源

2015-08-15 Oliver Ketley

此代碼是過時的。查看現代API（PDO，mysqli）和準備好的語句。並更改密碼 – Strawberry

SELECT * FROM your_table WHERE id NOT IN(1,2,3)

這應該做的伎倆。

來源

2015-08-15 21:44:38

噢，我忘了你可以將它們組合起來......捂臉...... –

我需要你的代碼位添加到我現有的查詢。 $ find_videos = mysql_query（「SELECT * FROM'videos' WHERE'keywords' LIKE'％$ search％'」）;我怎麼做？ –

@OliverKetley'$ find_videos =請求mysql_query（「SELECT * FROM視頻WHERE關鍵字LIKE '％$搜索％' 和ID NOT IN（1,2,3）」）;' –

如何查詢表，但忽略某些列，如ID =「1」和「2」

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