我也有類似的一個問題已經被問:Given start date and end date, reshape/expand data for each day between (each day on a row)擴大按日期排,同時保持所有其他變量
這是我的數據的子集(而不是所有的變量都包括在內;有43個變量總數):
start_date <- as.Date(c("1946-01-01", "1966-01-01","1979-03-01", "1966-01-01", "1988-05-01"))
end_date <- as.Date(c("1946-03-01","1966-03-01","1979-05-01", "1966-03-01", "1988-07-01"))
dyad_id <- c(260,260,260,306,306)
armsproc <- c("moderate", "low", "low", "low", "low")
gov_support <- c("explicit", "no", "no", "no", "explicit")
terrcont <- c("yes", "no", "no", "yes", "yes")
x <- data.frame(start_date, end_date, dyad_id, armsproc, gov_support, terrcont)
這是我的採樣數據的可視化:
start_date end_date dyad_id armsproc gov_support terrcont
1 1946-01-01 1946-03-01 260 moderate explicit yes
2 1966-01-01 1966-03-01 260 low no no
3 1979-03-01 1979-05-01 260 low no no
4 1966-01-01 1966-03-01 306 low no yes
5 1988-05-01 1988-07-01 306 low explicit yes
相反的數據範圍的,我想具有用於每個m月度數據start_date and end_date。此外,在上面鏈接的問題中沒有回答什麼問題,我希望所有剩餘列中的數據在該時間段內的所有月份都可以簡單複製。要清楚,我希望這個數據複製在每個dyad_id內完成。我想要的東西,看起來像這樣:
month dyad_id armsproc gov_support terrcont
1946-01-01 260 moderate explicit yes
1946-02-01 260 moderate explicit yes
1946-03-01 260 moderate explicit yes
1966-01-01 260 low no no
1966-02-01 260 low no no
1966-03-01 260 low no no
1979-03-01 260 low no no
1979-04-01 260 low no no
1979-05-01 260 low no no
1966-01-01 306 low no yes
1966-02-01 306 low no yes
1966-03-01 306 low no yes
1988-05-01 306 low explicit yes
1988-06-01 306 low explicit yes
1988-07-01 306 low explicit yes
我試着用類似於其他問題
x %>%
rowwise() %>%
do(data.frame(dyad_id=.$dyad_id, month=seq(.$start_date,.$end_date,by="1 month")))
建議代碼,但是這僅僅得到以下數據幀只有2列:
# A tibble: 6 x 2
dyadid month
<int> <date>
1 462 1946-06-01
2 462 1946-07-01
3 463 1952-04-01
4 464 1967-03-01
5 464 1967-04-01
6 464 1967-05-01
如果有人能夠幫助我,我將不勝感激!乾杯
在tidyr包中可能'expand'或'complete'可能有幫助嗎? – gjabel