2017-04-26 72 views
0

如何改進此腳本? 如何每次運行保存多個圖像。selenium webdriver機器人從本地html中提取散景圖像

帶有3個圖形的html立即加載,但帶有50個圖形的html加載了幾分鐘。所以這不是爲每個圖像重新加載頁面的最佳方式。

我每次運行只得到一個圖像。之後,我收到錯誤 消息: 陳舊元素引用:元素未附加到頁面文檔。

# encoding: utf-8 

from selenium import webdriver 
from selenium.webdriver.common.keys import Keys 

import os 

import sys 
reload(sys) 
sys.setdefaultencoding('utf-8') 

driver = webdriver.Chrome("/usr/lib/chromium-browser/chromedriver") 

url = 'file:\\\\\\%s/26w0.html' % (os.getcwd()) 

driver.get(url) 
elem = driver.find_element_by_class_name("bk-tool-icon-save") 
saves = driver.find_elements_by_class_name("bk-tool-icon-save") 

for i in range(len(saves)): 
    print i 
    driver.get(url) 
    elem = driver.find_element_by_class_name("bk-tool-icon-save") 
    saves = driver.find_elements_by_class_name("bk-tool-icon-save") 

    saves[i].click() 
    elem.send_keys(Keys.ENTER) 

這是寫在Python,但我很開放的建議, ,如果你知道的Java/.NET /任何其他平臺/語言的解決方案,歡迎您。

<!DOCTYPE html> 
 
<html lang="en"> 
 
    <head> 
 
     <meta charset="utf-8"> 
 
     <title>Bokeh Plot</title> 
 
     
 
<link rel="stylesheet" href="https://cdn.pydata.org/bokeh/release/bokeh-0.12.4.min.css" type="text/css" /> 
 
     
 
<script type="text/javascript" src="https://cdn.pydata.org/bokeh/release/bokeh-0.12.4.min.js"></script> 
 
<script type="text/javascript"> 
 
    Bokeh.set_log_level("info"); 
 
</script> 
 
     <style> 
 
      html { 
 
      width: 100%; 
 
      height: 100%; 
 
      } 
 
      body { 
 
      width: 90%; 
 
      height: 100%; 
 
      margin: auto; 
 
      } 
 
     </style> 
 
    </head> 
 
    <body> 
 
     
 
     <div class="bk-root"> 
 
      <div class="bk-plotdiv" id="c5c2aae1-5936-42f6-b4e3-9bc4b46efd06"></div> 
 
     </div> 
 
     
 
     <script type="text/javascript"> 
 
      (function() { 
 
      var fn = function() { 
 
      Bokeh.safely(function() { 
 
       var docs_json = {"2797a004-7f17-48fa-b80f-105be766d58d":{"roots":{"references":[{"attributes":{"fill_alpha":{"value":0.1},"fill_color":{"value":"#1f77b4"},"line_alpha":{"value":0.1},"line_color":{"value":"#1f77b4"},"size":{"units":"screen","value":8},"x":{"field":"x"},"y":{"field":"y"}},"id":"bb128c3f-68fb-4464-9d3f-c188b2ce8614","type":"Circle"},{"attributes":{"plot":{"id":"64a90e8d-fce9-4bbd-b044-1ceda097ba2d","subtype":"Figure","type":"Plot"},"ticker":{"id":"ab09a83a-42c4-44e8-919d-30796ac60bfe","type":"BasicTicker"}},"id":"b2cbd3ba-7dbd-400e-9971-227edc77fed7","type":"Grid"},{"attributes":{"format":"%.1f 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       var render_items = [{"docid":"2797a004-7f17-48fa-b80f-105be766d58d","elementid":"c5c2aae1-5936-42f6-b4e3-9bc4b46efd06","modelid":"fa51df2d-c281-4559-9fa2-05403688a06a"}]; 
 
       
 
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</html>

我不能手動長一段時間,因爲 需要數以千計的圖像做。

p.s. 到@ e1che 我固定的一些事情在我們的代碼:

for i in range(len(saves)): 
    print i 
    saves[i].click() 
    saves[i].send_keys(Keys.ENTER) 

看起來簡單,更好的,但也不能正常工作。

+0

當我加載頁面時,我看到3個初始圖形,但我從來沒有看到後來的50個。它應該如何工作? – JeffC

+0

是的,我知道,我附上了只有3個圖表的HTML文件, 你誤會了我。帶有許多圖形的html文件在我的筆記本電腦上,並沒有附在那裏,我只想提及一個規模和性能問題。 – lvcpp

+0

你應該更新這個問題,因爲你對50張圖的評論不清楚。不過我想現在我明白了。我已經更新了我的答案以包含單獨的文件,但它應該可以在每個文件中使用多個圖表。 – JeffC

回答

0

您的主要問題來自您給您的驅動程序提供「新」url。 你應該簡化一下你的foreach循環。

for i in range(len(saves)): 
    print i 
    elem_loop = elem[i] 
    saves_loop = saves[i] 
    saves_loop[i].click() 
    elem_loop.send_keys(Keys.ENTER) // elem_loop[i] ? you click on the same element for each image ? 
+0

謝謝,但這個片段不會工作,因爲 elem = driver.find_element_by_class_name(「bk-tool-icon-save」) elem是一個元素,而不是元素列表。 – lvcpp

+0

爲我在範圍內(len(節省)): print i 保存[i] .click() 保存[i]。send_keys(Keys.ENTER) 看起來更簡單和更好,但也不能正常工作。 – lvcpp

0

我不知道你指的是這個問題,但您所遇到的主要問題是,你點擊頁面上的所有保存按鈕之前重新加載頁面的50張圖片。你可以用下面的代碼修復它。

// files is an array of string which is the path to the files on disk 
for file in files 
    driver.get(file) 
    for e in driver.find_elements_by_class_name("bk-tool-icon-save"): 
     e.click() 

這應該保存所有加載的圖像。一旦您提供了更多關於其他50張圖片加載方式/時間的詳細信息,我們可以回答該部分。你應該等待,直到所有的圖像加載和上面的代碼將工作並保存所有圖像。

此外,elem只是saves集合中的第一個元素,因此不需要同時存儲這兩個元素。我不確定send_keys()的用途......它不應該被需要,所以我也刪除了它。

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