我有一個表格:如何從選中的複選框,這是在一個表中獲取價值
<form action='send.php' method ='post'>
SMS: <input type='checkbox' name = 'sms'>
E-mail: <input type='checkbox' name = 'email' id='mailcheck'><br>
<TEXTAREA NAME='message' WRAP='virtual' COLS='40' ROWS='3'>
</TEXTAREA><br>
<input type ='submit' name ='Send' size = '10' value = 'send'>
</form>
我有一個結構從數據庫表:
$table = "<table border=1 width=100% align=center>\n";
$table .= "<tr>\n";
$i = 1;
while ($i < mysql_num_fields($queryResult)) {
$meta = mysql_fetch_field($queryResult, $i);
$i++;
$table .= "<td>".$meta->name."</td>\n";
}
$table .= "<td> Выбрать все: <input type='checkbox' name='maincheck' value='main' id='chkSelectAll'</td>\n";
$table .= "</tr>\n";
$i = 1;
while ($row = mysql_fetch_assoc($queryResult)){
$table .= "<tr>\n";
$table .= "<td>".$row['name']."</td>\n";
$table .= "<td>".$row['post']."</td>\n";
$table .= "<td>".$row['section']."</td>\n";
$table .= "<td>".$row['company']."</td>\n";
$table .= "<td>".$row['phone_number']."</td>\n";
$table .= "<td>".$row['email']."</td>\n";
$table .= "<td>".$row['status']."</td>\n";
$table .= "<td>".$row['lock_time']."</td>\n";
$table .= "<td>".$row['reason_for_blocking']."</td>\n";
$table .= "<td><input type='checkbox' class=".check." name='cbname3[]' id='chkItems' value=".$row['id']." /></td>";
$table .= "</tr>\n";
$i++;
}
$table .= "</table>\n";
echo $table;
我想利用價值從表格中檢查複選框到send.php。
我不能拿這個$ _POST,因爲它是不同的形式!
可能重複的[如何獲取PHP的選中複選框的值?](http://stackoverflow.com/questions/6291370/how-to-get-value-of-checked-checkbox-in-php) – 2011-06-09 12:11:50
這是另一個問題。沒有一個人不明白我問了什麼。 – Divers 2011-06-09 12:13:56
- 所以它是同一個問題,但是你表達得很糟糕,所以你把重寫作爲一個新問題而不是修復現有問題? – Quentin 2011-06-09 12:20:20