我在向MySQL表格回顯MySQL表格,但是我的一些數據庫字段爲空。當數據庫字段爲空,我怎麼可以指定一個替代文本(而不是它只是顯示空白將MySQL表格複製到顯示空字段文本的HTML表格
下完美的作品(含空白單元格):
<?php
include("../config.php");
$link = mysqli_connect("$db_host" , "$db_user" , "$db_password" , "$db");
mysqli_select_db($link, $db);
$result = mysqli_query($link,"SELECT * FROM the_table");
echo "<table border='1'>
<tr>
<th>Name</th>
<th>Email</th>
<th>Phone</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['phone'] . "</td>";
echo "</tr>";
}
echo "</table>";
?>
我想答案應該看的東西像這樣(但它不工作):
if (empty($row['name'])) {
echo "<td>Not Specified</td>";
} else {
echo "<td>" . $row['name'] . "</td>";
}
建議
嘗試微調如果(空(修剪($行[ '名稱']))) – 2014-09-05 18:59:13