AS2：兩個日期

Question

我使用這個腳本目前確定兩個日期之間的差值之間計算天：

// Slide_Tracker[?].date_int are results from the built in function getTime() 
var current_date = new Date(Slide_Tracker[i].date_int); 
var past_date:Date = new Date(Slide_Tracker[i - 1].date_int); 
var date_diff:Number = Math.round((current_date - past_date)/86400000); 

的問題，這是我要監控的實際物理一天的變化，所以如果有人訪問的應用程序在下午11點59分，然後5分鐘後回來，這將記錄爲1天的差異（新的一天），這個當前腳本需要至少12個小時才能在兩個日期之間通過，作爲新的一天註冊。

我曾考慮過使用日期編號等，但因爲幾個月和幾年如此不同，它是相當複雜的路線，必須有一些更簡單的方法。

Answer 1

作爲一個供參考，以下AM的日期和午夜之間的區別是：

// dt is the start date 
var diff:Number = 
     new Date(dt.getYear(), dt.getMonth(), dt.getDate() + 1) - dt.getTime() 

但它是最容易簡單地四捨五入到第二天，然後從那裏開始：

var dt:Date = new Date(Slide_Tracker[i - 1].date_int); 
var past_date = // start at the next day to only deal w/ 24 hour increments 
    new Date(dt.getYear(), dt.getMonth(), dt.getDate() + 1); 
dt = new Date(Slide_Tracker[i].date_int); 
var current_date = 
    new Date(dt.getYear(), dt.getMonth(), dt.getDate() + 1); 
var date_diff:Number = Math.round((current_date.getTime() - 
            past_date.getTime())/86400000); 

您的另一種選擇是圓的投入：

// rounds a timestamp *down* to the current day 
function getBaseDay(val:Number):Number 
{ 
    return Math.floor(val/86400000) * 86400000 
} 

var current_date = new Date(getBaseDay(Slide_Tracker[i].date_int)); 
var past_date:Date = new Date(getBaseDay(Slide_Tracker[i - 1].date_int)); 
var date_diff:Number = Math.round((current_date.getTime() - 
            past_date.getTime())/86400000); 

Answer 2

像這樣的東西應該工作：

public boolean isNewDay(current:Date, past:Date):Boolean 
{ 
    // check the days of the month first 
    if(current.date != past.date) 
     return true; 

    // check the months in case they came back on the same day of the next month 
    if(current.month != past.month) 
     return true; 

    // finally check the year, in case they came back on the same day the next year 
    if(current.fullYear != past.fullYear) 
     return true; 

    return false; 
} 

即使你已經接受了答案

，這裏是一個更新功能：

public function getNumberOfDays(current:Date, past:Date):int 
{ 
    // get the number of millis between the two dates 
    var millis:Number = current.time - past.time; 

    // a day in millis is 1000 (s) * 60 (m) * 60 (h) * 24 (day) 
    var day:Number = 1000 * 60 * 60 * 24; 

    // get the number of days 
    var numDays:int = int(millis/day); 

    // create midnight of the current day 
    if (numDays == 0) 
    { 
     // if our numDays is 0, check if the current date is after midnight and the 
     // previous date was before midnight the previous day, in which case, count 
     // it as another day 
     var midnight:Date = new Date(current.fullYear, current.month, current.date); 
     if (current.time > midnight.time && past.time < midnight.time) 
      numDays++; 
    } 

    return numDays; 
} 

它適用於所有的測試情況下，我已經試過（午夜至23.59.59 = 0天，23.59到00.05 = 1天）