如何見下表安排在PHP

Question

assending爲了我不能夠按升序排列輸出表ORDER BY ASC不工作中流露出表但表元素
我的代碼如下工作：

<?php 
$result = mysql_query("SHOW TABLES FROM st_db_1"); 
while($row = mysql_fetch_row($result)) { 
    $result_tb = mysql_query("SELECT id FROM $row[0] LIMIT 1"); 
    $row_tb=mysql_fetch_array($result_tb); 

    //checking for availbility of result_tb 
    if (!$result_tb) { 
       echo "DB Error, could not list tables\n"; 
       echo 'MySQL Error: ' . mysql_error(); 
       exit; 
    } 
    echo "<a href=exa.php?id=$row_tb[id]>{$row[0]}<br/><a/>" ; 
} 
mysql_free_result($result); 
mysql_free_result($result_tb); 
?> 

Answer 1

$result_tb = mysql_query("SELECT id FROM $row[0] LIMIT 1 s ORDER BY id ASC"); 

，你必須使用ORDER BY

Answer 2

select TABLE_NAME 
from information_schema.TABLE_CONSTRAINTS 
order by TABLE_NAME ASC; 

訂購table_names。

見（在頁面的底部）：http://bugs.mysql.com/bug.php?id=14473

Answer 3

如果你的意思是，

SHOW TABLES FROM st_db_1 ORDER BY x ASC 

不工作，那是因爲沒有這樣的語法（HTTP：/ /dev.mysql.com/doc/refman/5.0/en/show-tables.html）。你可以，但是，通過PHP排序結果，然後選擇的每個表：

<?php 
$result = mysql_query("SHOW TABLES FROM st_db_1"); 
$tableArr = array(); 

while($row = mysql_fetch_row($result)) { 
    $tableArr[] = $row; 
} 

usort($tableArr, function cmp($a, $b) { 
    if ($a[0] == $b[0]) 
     return 0; 
    return ($a[0] < $b[0]) ? -1 : 1; 
} 

foreach($tableArr as $row) { 
    $result_tb = mysql_query("SELECT id FROM $row[0] LIMIT 1"); 
    $row_tb = mysql_fetch_array($result_tb); 

    //checking for availbility of result_tb 
    if (!$result_tb) { 
     echo "DB Error, could not list tables\n"; 
     echo 'MySQL Error: ' . mysql_error(); 
     exit; 
    } 
    echo "<a href=exa.php?id=$row_tb[id]>{$row[0]}<br/><a/>"; 
} 

mysql_free_result($result); 
mysql_free_result($result_tb);