將dd MMM yyyy轉換爲unix時間

Question

我有一個字符串，我從dd MMM yyyy格式的文件中提取，我想將其轉換爲unixtime進行監視。

舉個例子：

19 Jul 2017 

我想顯示爲：

1500422400 

每一番搜索我想以下幾點：

$dateValue = "19 Jul 2017" 
$date1 = Get-Date -Date "01/01/1970" 
$date2 = Get-Date -Date $dateValue 
$unixtime = Get-Date (New-TimeSpan -Start $date1 -End $date2).TotalSeconds 

我得到以下錯誤：

Get-Date : Cannot bind parameter 'Date'. Cannot convert value "1530662400" to type "System.DateTime". Error: "String was not recognized as a valid DateTime." At D:\cppib\bin\snlStatus.ps1:19 char:22 + $unixtime = Get-Date (New-TimeSpan -Start $date1 -End $date2).TotalSeconds + ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ + CategoryInfo : InvalidArgument: (:) [Get-Date], ParameterBindingException + FullyQualifiedErrorId : CannotConvertArgumentNoMessage,Microsoft.PowerShell.Commands.GetDateCommand

Answer 1

在列表行中刪除Get-Date因爲它試圖將時間跨度的總秒數轉換爲DateTime。

$dateValue = "19 Jul 2017" 
$unixtime = ((Get-Date $dateValue)-(Get-Date "01 JAN 1970")).TotalSeconds 
Write-Host $unixtime 

進一步檢查，發現這個

$dateValue = "19 Jul 2017" 
$unixtime = Get-Date $dateValue -UFormat %s 
Write-Host $unixtime 

這回同樣的事情。

來源：Get-Date

Answer 2

$unixstart = Get-Date -Date "01/01/1970" 
$date2 = Get-Date $dateValue 

$unixtime = (New-TimeSpan -Start $unixstart -End $date2).TotalSeconds 

Write-Host $unixtime